Question

Sierra is selling bracelets to raise money for the Language Club at school. Each bracelet with yellow beads sells for $5. Each bracelet with orange beads sells for $6. She raised $660 for the club. The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads. Let y represent the number of bracelets with yellow beads and r represent the number of bracelets with orange beads.Which system of equations will solve for the number of each type of bracelet sold? 5 y + 6 r = 660. y = 2 r + 8. 6 y + 5 r = 660. y = 2 r + 8. 5 y + 6 r = 660. y = r + 8. 6 y + 5 r = 660. r = 2 y + 8.

Answer 1

Answer:

Correct answer is:

$5y+6r=660\\y=2r+8$

Step-by-step explanation:

Given that Number of bracelets with yellow beads is represented by $y$

Each bracelet with yellow beads is sold for $5.

Total money raised by bracelets with yellow beads = Number of bracelets sold $\times$ Money raised by sale of one such bracelet = $5y$

Also Given that Number of bracelets with Orange beads is represented by $r$

Each bracelet with orange beads is sold for $6.

Total money raised by bracelets with orange beads = Number of bracelets sold $\times$ Money raised by sale of one such bracelet = $6r$

Given that total money raised by sale of both type of bracelets is $660.

so, the first equation becomes:

$5y+6r=660 ....... (1)$

It is also given that "The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads"

$\Rightarrow r =2r+8 ...... (2)$

So, by equation (1) and (2), the system of equations is:

$5y+6r=660\\y=2r+8$