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just olya [345]
3 years ago
12

What is the equation that is perpendicular and passes through 8,3

Mathematics
1 answer:
ss7ja [257]3 years ago
6 0
Y = 4x + 5
slope = 4
perpendicular, slope = - 1/4

passing thru (8,3)

equation
y - 3 = -1/4 (x - 8)
y - 3 = -1/4x + 2
y = -1/4x +5

answer is D. y = -1/4x +5
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How do i graph the equation y= -4x - 1
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Answer:

  see attached

Step-by-step explanation:

Find the y-values corresponding to x-values of 0 and 1, then plot those points and draw a line through them.

For x=0, ...

  y = -4·0 -1 = -1 . . . . the point is (0, -1) . . . the y-intercept

For x=1, ...

  y = -4·1 -1 = -5 . . . . the point is (1, -5)

The attached graph shows these points and the line through them.

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Ne4ueva [31]

Answer:

81

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7 0
3 years ago
given line passes through the points (-4, -3) and( 4, 1) what is the equation in point slope form of the line that's perpendicul
Diano4ka-milaya [45]

Answer:

y= -2x-5

Step-by-step explanation:

First find the gradient of the first line

m =  \frac{y2 - y1}{x2 - x1}

m=

\frac{1 -  - 3}{4 -  - 4}

m=

\frac{4}{8}

m=1/2

From this we can find the gradient of the perpendicular line, or the normal.

m1 × m2 = -1

Replace m1 with 1/2

1/2 × m2 = -1

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Substitute values into

y-y1=m (x-x1)

y-3=-2 (x+4)

y-3=-2x -8

y=-2x-5

6 0
3 years ago
Read 2 more answers
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