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just olya [345]
3 years ago
12

What is the equation that is perpendicular and passes through 8,3

Mathematics
1 answer:
ss7ja [257]3 years ago
6 0
Y = 4x + 5
slope = 4
perpendicular, slope = - 1/4

passing thru (8,3)

equation
y - 3 = -1/4 (x - 8)
y - 3 = -1/4x + 2
y = -1/4x +5

answer is D. y = -1/4x +5
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5) Find the distance between -9 and 12 on a number line.​
kati45 [8]

Answer: Hope this helps!!!

Step-by-step explanation:Absolute Value: You need to find how far away both numbers are from zero, then add these values together to see how far apart these numbers. The absolute value of nine, |-9| is 9, and |12| is 12. This means that the nine is nine spots away from zero, and twelve is twelve spots from zero. This means that the numbers are 20 units from each other.

Distance -9 is from 12 You need to find how much of an increase from nine you need to reach the twelve. So -9 + ? = 12. What number can you add to equal twelve? You can add 20 to make the equation true. (? = 20) The distance from -9 to 12 is a positive 20.

Distance from 12 to -9 This is similar to the previous example. What number can you insert to make the 12 equal the negative nine? 12 - ? = -9. The number would be -20, which means that 12 is 20 spots away from the negative nine, as it took at negative twenty to get us to the negative nine.

3 0
2 years ago
an equilateral triangle and a regular pentagon have the same perimeter. Each side of the pentagon is 3 inches shorter than each
klemol [59]
The answer is 4.5 for the side length of the pentagon and 7.5 is the side length for the triangle because 7.5*3(3 sides) = 22.5 and 4.5*5(5 sides)= 22.5. The perimeter is 22.5
6 0
3 years ago
⦁ Write an equation of a line in slope intercept form (y = mx + b) with slope 1/3 going through the point (-6, 2). Show your wor
Zepler [3.9K]

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-6)}) \\\\\\ y-2=\cfrac{1}{3}(x+6)\implies y-2=\cfrac{1}{3}x+2\implies y=\cfrac{1}{3}x+4

3 0
2 years ago
Given: AB = 4 AC = 6 What point is in the interior of both circles? H. A. B.
AleksAgata [21]

Answer:

Point A is in the interior of both circles

Step-by-step explanation:

<u><em>Verify each point</em></u>

we know that

Point H is in the interior of greater circle but is outside smaller circle

Point A is the center both circles, then is in the interior of greater circle and is in the interior of smaller circle

Point B is on the smaller circle and is in the interior of greater circle

therefore

Point A is in the interior of both circles

5 0
3 years ago
Compare and contrast the difference between "simplify a fraction" and "simplify a radical."
Ne4ueva [31]
Simplifying a fraction means most likely having it remain as a fraction and not a whole number and it can be converted as a decimal.

on the other hand, simplifying a radical, you would have no remainders, fractions, or decimals after simplifying.

thats the difference.
im not sure about similarities
8 0
3 years ago
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