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4 years ago

What is the equation that is perpendicular and passes through 8,3

Mathematics

1 answer:

ss7ja [257]4 years ago

6 0

Y = 4x + 5
slope = 4
perpendicular, slope = - 1/4

passing thru (8,3)

equation
y - 3 = -1/4 (x - 8)
y - 3 = -1/4x + 2
y = -1/4x +5

answer is D. y = -1/4x +5

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Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2

Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$5x^2-6x-2=0$

Define the variables:

a = 5
b = -6
c = -2

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}$

$\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{76}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}$

$\implies x=\dfrac{6 \pm2\sqrt{19}}{10}$

$\implies x=\dfrac{3 \pm \sqrt{19}}{5}$

Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}$

Learn more about the quadratic formula here:

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3 0

2 years ago

Read 2 more answers

There are 3 different highways from City W to

devlian [24]

Answer:

6 x 4 you have 4 numbers and each can be put in 6 different ways. so it is 24 i think

Step-by-step explanation:

3 0

3 years ago

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Given m||n, find the value of x. m t (5x-5) (6x-27)

almond37 [142]

Step-by-step explanation:

due to the laws of symmetry of the angles of 2 crossing lines (and parallel lines are simply repeating and mirroring these angles), both angles must be equal.

5x - 5 = 6x - 27

-5 = x - 27

x = 22

4 0

2 years ago

B(x)=x+4, what is b(-10)

vovikov84 [41]

Answer:

B(-10)=-6

Step-by-step explanation:

we have

B(x)=x+4

we know that

B(-10) is the value of the function B(x) for the value of x=-10

substitute the value of x=-10 in the function

B(-10)=-10+4=-6

therefore

B(-10)=-6

8 0

3 years ago

How many solutions are there to the following system of equations?

sweet [91]

$4x-8y=0 \\
\underline{-3x+8y=-7} \\
4x-3x=0-7 \\
x=-7 \\ \\
4x-8y=0 \\
4 \times (-7)-8y=0 \\
-28-8y=0 \\
-8y=28 \\
y=\frac{28}{-8} \\
y=-\frac{7}{2} \\ \\
 \left \{ {{x=-7} \atop {y=-\frac{7}{2}}} \right.$

There is one solution to this system of equations. The answer is B.

6 0

3 years ago

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