What is the available vector for each resource and the need matrix for each thread. Note that an available vector depicts the qu
antities of resources of each type that are available in the system after current allocation. The need matrix depicts of the quantities of resources of each type still needed by each thread, with each column corresponding to a thread and each row corresponding to a resource and an entry in location [i, j] of the matrix showing the quantity of a resource rj still needed by a thread ti.
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Solution :
include
include
void parsename(
, char first
char last
{
// to_get_this_function_working_immediately, _irst
// stub_it_out_as_below._When_you_have_everything_else
// working,_come_back_and_really_parse_full_name
// this always sets first name to "Noah"
int i, j = 0;
for(i = 0; full[i] != ' '; i++)
first[j++] = full[i];
first[j] = '\0';
// this always sets last name to "Zark"
j = 0;
strcpy(last, full+i+1);
// replace the above calls with the actual logic to separate
// full into two distinct pieces
}
int main()
{
char full[40], first[20], last[20];
double hours[5];
// ask the user to enter full name
printf("What is your name? ");
gets(full);
// parse the full name into first and last
parse_name(full, first, last);
// load the hours
for(int i = 0; i < 5; i++)
{
printf("Enter hours for day %d: ", i+1);
scanf("%lf", &hours[i]);
}
// create the time card
FILE* fp = fopen("timecard.txt", "w");
fprintf(fp, "First Name: %s\n", first);
fprintf(fp, "Last Name: %s\n", last);
double sum = 0.0;
for(int i = 0; i < 5; i++)
{
fprintf(fp, "Day %i: %.1lf\n", i+1, hours[i]);
sum += hours[i];
}
fprintf(fp, "Total: %.1f\n", sum);
printf("Timecard is ready. See timecard.txt\n");
return 0;
}