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Otrada [13]
3 years ago
9

Two equal and opposite charges separated by a distance, d, experience an attractive force,

Physics
2 answers:
Rudik [331]3 years ago
7 0
F =  \frac{qQC}{ d^{2} }

d↓\frac{1}{2}
F↑4
murzikaleks [220]3 years ago
7 0
The answer to the question you asked is 4F
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A bus start from rest and then moves with a constant acceleration of 2m/s square. calculate its time of traven if its final velo
pshichka [43]

Answer:

Its Answer is 10 s.

Explanation:

As acceleration is defined as time rate of change of velocity. So,

a =  ( vf - vi ) ÷ t

2 = (20 - 0 ) ÷ t

2 =  20 ÷  t

t = 20 ÷ 2

t  = 10 s

We have put initial velocity as zero because  body is starting from rest.

<em>Hope it helps.</em>

5 0
3 years ago
an 18 ohm resistor and a 6 ohm resistor are connected in parallel to a battery, and the current in the 18 ohm resistor is found
riadik2000 [5.3K]

With 0.45 amp flowing through an 18-ohm resistor, the voltage across it is

       V  =  I R  =  (0.45) x (18)  =  <em>8.1 volts .</em>

"But I asked for the battery voltage!  That's the voltage across the resistor."

The ends of the resistor are connected directly to the battery terminals.
They're the same voltage.

"But what about the 6-ohm resistor ?  Where does that figure in ?"

In parallel, it doesn't.  It's also connected directly across the battery,
and it has its own current. 

In parallel, neither resistor knows or cares whether or not there are
any other resistors present.  In parallel, it makes no dif.


3 0
3 years ago
The amount of force we need to move an object is proportional to the amount of work done - the __________ force used, the more w
Vanyuwa [196]

Answer:

stronger.

pls follow me.

7 0
3 years ago
A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equa
ivann1987 [24]

Answer:

The moment of inertia of the wheel is 0.593 kg-m².

Explanation:

Given that,

Force = 82.0 N

Radius r = 0.150 m

Angular speed = 12.8 rev/s

Time = 3.88 s

We need to calculate the torque

Using formula of torque

\tau=F\times r

\tau=82.0\times0.150

\tau=12.3\ N-m

Now, The angular acceleration

\dfrac{d\omega}{dt}=\dfrac{12.8\times2\pi}{3.88}

\dfrac{d\omega}{dt}=20.73\ rad/s^2

We need to calculate the moment of inertia

Using relation between torque and moment of inertia

\tau=I\times\dfrac{d\omega}{dt}

I=\dfrac{I}{\dfrac{d\omega}{dt}}

I=\dfrac{12.3}{20.73}

I= 0.593\ kg-m^2

Hence, The moment of inertia of the wheel is 0.593 kg-m².

5 0
4 years ago
A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate
diamong [38]

To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

\Delta S = \frac{Q}{T}

Where,

Q = Heat transfer

T = Temperature

On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is

W = Q_{source}-Q_{sink}

According to the data given we have to,

Q_{source} = 200000Btu

T_{source} = 1500R

Q_{sink} = 100000Btu

T_{sink} = 600R

PART A) The total change in entropy, would be given by the changes that exist in the source and sink, that is

\Delta S_{sink} = \frac{Q_{sink}}{T_{sink}}

\Delta S_{sink} = \frac{100000}{600}

\Delta S_{sink} = 166.67Btu/R

On the other hand,

\Delta S_{source} = \frac{Q_{source}}{T_{source}}

\Delta S_{source} = \frac{-200000}{1500}

\Delta S_{source} = -133.33Btu/R

The total change of entropy would be,

S = \Delta S_{source}+\Delta S_{sink}

S = -133.33+166.67

S = 33.34Btu/R

Since S\neq   0 the heat engine is not reversible.

PART B)

Work done by heat engine is given by

W=Q_{source}-Q_{sink}

W = 200000-100000

W = 100000 Btu

Therefore the work in the system is 100000Btu

4 0
4 years ago
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