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DiKsa [7]
3 years ago
13

If a car is moved 10 meters and 3 Newtons of force is needed to move the car, what amount of work has been done?

Physics
1 answer:
Bingel [31]3 years ago
3 0

Answer:

Work=30J

Explanation:

Work=F*x

F=3N

x=10m

Work=3*10=30J

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Why does a 10 gram piece if copper take up more space than a 10 gram piece of gold
algol [13]

Answer:

because the mass of the copper is higher than the mass of the gold.

Explanation:

7 0
3 years ago
Question 5- A gas occupies 60 liters at a pressure of 40.0 mm Hg. What is the volume when the pressure is
shtirl [24]

Answer:

40L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 60L

P1 (initial pressure) = 40mmHg

V2 (final volume) =?

P2 (final pressure) = 60mmHg

Using P1V1 = P2V2, the final volume can be obtain as illustrated below:

P1V1 = P2V2

40 x 60 = 60 x V2

Divide both side by 60

V2 = (40 x 60)/60

V2 = 40L

Therefore, the final volume is 40L

3 0
4 years ago
The body starts from rest and moves evenly accelerated. At the end of the eighth second of movement, its speed is 16 m / s. Calc
cricket20 [7]

Answer:

a = 2 m/s²

v₄ = 8 m/s

Explanation:

We can find the final speed at the end of eight second by using first equation of motion:

v_{f} = v_{i} + at\\

where,

vf = final velocity at 8th second = 16 m/s

vi = initial velocity = 0 m/s

a = acceleration = ?

t = time = 8 s

Therefore, using the values in the equation we get:

16\ m/s = 0\ m/s + a(8\ s)\\\\a = \frac{(16\ m/s)}{8\ s}

<u>a = 2 m/s²</u>

<u></u>

Now, we can apply same equation of motion for 4 seconds of motion to find the velocity at the end of 4th second (v₄):

v_{4} = 0\ m/s + (2\ m/s^2)(4\ s)\\

<u>v₄ = 8 m/s</u>

6 0
3 years ago
Unlike a phonograph record that has a constant angular speed, a CD scans information at a constant linear speed (130 cm/s). Does
Oksi-84 [34.3K]

Answer: A CD rotate at a varying angular speed

6 0
4 years ago
Photons of wavelength 199 nm are incident on a metal plate in a photocell, and electrons are ejected. A stopping potential of 1.
Elza [17]

Answer:

λ = 11.29 x 10⁻⁷ m = 1129 nm

Explanation:

According to the law of conservation of energy:

Photon\ Energy = Energy\ Applied\ by\ Stopping\ Potential\\\\\frac{hc}{\lambda} = eV\\\\\lambda = \frac{hc}{eV}

where,

λ = maximum wavelength = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = stopping poteential = 1.1 V

Therefore,

\lambda = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{(1.6\ x\ 10^{-19}\ C)(1.1\ V)}

<u>λ = 11.29 x 10⁻⁷ m = 1129 nm</u>

8 0
3 years ago
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