Would you expect older volcanoes to be seamounts and islands

Two hockey players , big Jim and little Tim collide head on and get tangled while going for the puck 65kg time was traveling at

12345 [234]

I will assume that big Joe is big Jim. The equation for the momentum is p=m*v, where m is the mass of the body and v is the velocity. Big Joe has a mass m=105 kg and speed v=5.2 m/s. When we input the numbers:

p=105*5.2=546 kg*(m/s).

So big Joe's momentum before the collision is p=546 kg*(m/s).

7 0

3 years ago

20 POINTS

Harlamova29_29 [7]

Answer: check the link

hope it helps

Explanation:

3 0

3 years ago

Read 2 more answers

1. A passenger in the rear seat of a car moving at a steady speed is at rest relative to

makvit [3.9K]

The front seat of the car.

7 0

3 years ago

Read 2 more answers

500 nm light passes through a circular aperture that has a diameter d = 30.0 Î¼m. A diffraction pattern forms on a screen 350 mm

larisa86 [58]

Complete Ques

Answer:

The value is $A = 0.00214 \ m^2$

Explanation:

From the question we are told that

The wavelength is $\lambda = 500 \ nm = 500 *10^{-9} \ m$

The diameter of the aperture is $d = 30 \mu m = 30*10^{-6} \ m$

The distance of the screen from the aperture is $D = 350 \ m m = 0.350 \ m$

Generally the distance from the center the the edge of the central bright fringe is magmatically reparented as

$y = \frac{m * \lambda * D}{d}$

Generally m = 1 because after the central bright fringe we have the first order fringe

So

$y = \frac{1 * 500 *10^{-9} * 0.350}{30*10^{-6}}$

=> $y =0.00583 \ m$

Generally the area of the central bright fringe

$A = 2 \pi * y^2$

=> $A = 2 * 3.142 * 0.00583^2$

=> $A = 0.00214 \ m^2$

3 0

3 years ago

Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th

gregori [183]

Complete Question

Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and thus our bodies) as three isotopes: Potassium-39, Potassium-40, and Potassium-41. Their current abundances are 93.26%, 0.012% and 6.728%. A typical human body contains about 3.0 grams of Potassium per kilogram of body mass. 1. How much Potassium-40 is present in a person with a mass of 80 kg? 2. If, on average, the decay of Potassium-40 results in 1.10 MeV of energy absorbed, determine the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body. Assume an RBE of 1.2. The half-life of Potassium-40 is $1.28 * 10^9$ years.