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3 years ago

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500 nm light passes through a circular aperture that has a diameter d = 30.0 Î¼m. A diffraction pattern forms on a screen 350 mm

from the aperture. Calculate the area of the central bright fringe.

1 answer:

larisa86 [58]3 years ago

3 0

Complete Ques

Answer:

The value is $A = 0.00214 \ m^2$

Explanation:

From the question we are told that

The wavelength is $\lambda = 500 \ nm = 500 *10^{-9} \ m$

The diameter of the aperture is $d = 30 \mu m = 30*10^{-6} \ m$

The distance of the screen from the aperture is $D = 350 \ m m = 0.350 \ m$

Generally the distance from the center the the edge of the central bright fringe is magmatically reparented as

$y = \frac{m * \lambda * D}{d}$

Generally m = 1 because after the central bright fringe we have the first order fringe

So

$y = \frac{1 * 500 *10^{-9} * 0.350}{30*10^{-6}}$

=> $y =0.00583 \ m$

Generally the area of the central bright fringe

$A = 2 \pi * y^2$

=> $A = 2 * 3.142 * 0.00583^2$

=> $A = 0.00214 \ m^2$

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3 years ago