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4 years ago

1. A passenger in the rear seat of a car moving at a steady speed is at rest relative to

Physics

2 answers:

makvit [3.9K]4 years ago

7 0

The front seat of the car.

lbvjy [14]4 years ago

3 0

Answer: A passenger in the rear seat of a car moving at a steady speed is at rest relative to the front seat of the car.

Explanation: From the Newton's first law, if the object is moving with uniform speed or if the object is in a state of rest then it will remain in that state unless it is acted upon by the external force.

In the given situation, a passenger in the rear seat of a car moving at a steady speed is at rest relative to the front seat of the car because the front seat of the car is also at rest in the car relative to the passenger. Only the car is moving.

Therefore, a passenger in the rear seat of a car moving at a steady speed is at rest relative to the front seat of the car.

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Starting from rest near the surface of the Earth, a 25-kg beam slides 12 m down a vertical pine tree, and has a speed of 6 m/s j

Mamont248 [21]

Answer:

The frictional force acting on the bear during the slide is 207.5 N

Explanation:

Given;

mass of beam, m = 25-kg

vertical height, h = 12 m

speed of fall, v = 6 m/s

Change in potential energy of the beam:

ΔP.E = -mgh = - 25 x 9.8 x 12 = -2940 J

Change in kinetic energy of the beam:

Δ K.E = ¹/₂mv² = ¹/₂ x 25 x (6)² = 450 J

Change in thermal energy of the system due to friction:

ΔE = - (ΔP.E + Δ K.E)

ΔE = - (-2940 J + 450 J)

ΔE = 2940 J - 450 J = 2490 J

Frictional force (in N) acting on the bear during the slide:

F x d = Fk x h = ΔE

Where;

Fk is the frictional force

Fk = ΔE/h

Fk = 2490J / 12m

Fk = 207.5 N

Therefore, the frictional force acting on the bear during the slide is 207.5 N

3 0

3 years ago

How do we know the sun is supported by nuclear fusion?

Leya [2.2K]

we know that the sun is supported by nuclear fusion because the sun is a main-sequence star, meaning it has to use nuclear fusion to keep itself going, no nuclear fusion, no sun.

i hope this helps!

3 0

4 years ago

A woman fires a rifle with barrel length of 0.5400 m. Let (0, 0) be where the 125 g bullet begins to move, and the bullet travel

dybincka [34]

Answer:

Explanation:

Given that,

Length of barrel =0.54m

Mass of bullet=125g=0.125kg

Force extend

F=16,000+10,000x-26,000x²

a. Work done is given as

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=0.54m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=0.54m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=0.54m

W= 16,000(0.54) + 5000(0.54²) - 8666.667(0.54³) +0+0-0

W=8640+1458-1364.69

W=8733.31J

The workdone by the gas on the bullet is 8733.31J

b. Work done is given as

Work done when the length=1.05m

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=1.05m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=1.05m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=1.05mm

W= 16,000(1.05) + 5000(1.05²) - 8666.667(1.05³) +0+0-0

W=16800+5512.5-10032.75

W=12,279.75J

The workdone by the gas on the bullet is 12,279.75J

3 0

4 years ago

Two microwave signals of nearly equal wavelengths can gener- ate a beat frequency if both are directed onto the same microwave d

Sonja [21]

Answer:

the longer wavelength is 1.2552 cm

Explanation:

given that

beat frequency $f_{b}$ = 100 MHz = 100 × 10⁶ Hz

λ₁ = 1.250 cm = 0.0125 m

we know that beat frequency $f_{b}$ of two simultaneous frequencies f₁ and f₂ is expressed as;

$f_{b}$ = | f₁ - f₂ |

we know that microwave travels at a speed of light, so for any electromagnetic wave traveling at speed of light c with wavelength λ; frequency is;

f = c / λ

hence our beat frequency $f_{b}$ becomes

$f_{b}$ = c ( 1/λ₁ - 1/λ₂)

to find the longer wavelength, λ₂

$f_{b}$ = c ( 1/λ₁ - 1/λ₂)

divide both side by c

$f_{b}$ /c = ( 1/λ₁ - 1/λ₂)

1/λ₂ = 1/λ₁ - $f_{b}$ /c

λ₂ = [1/λ₁ - $f_{b}$ /c ]⁻¹

so we substitute in our values

we know that speed of light c = 3 × 10⁸

λ₂ = [ (1/0.0125) - (100 × 10⁶ /3 × 10⁸) ]⁻¹

λ₂ = [80 - 0.3333 ]⁻¹

λ₂ = [79.6667 ]⁻¹

λ₂ = 0.01255 m

λ₂ = 0.012552 × 100 cm

λ₂ = 1.2552 cm

Therefore, the longer wavelength is 1.2552 cm

7 0

3 years ago

A man with a weight of 450 N climbs a ladder to a height of 5.2 meters. How much work did he do?

jeka57 [31]

Answer:

the work done by him is 2,340 joules

Explanation:

The computation of the work done by him is shown below:

= Weight of man × height

= 450 N × 5.2 meters

= 2,340 joules

Hence, the work done by him is 2,340 joules

We simply multiply the man weight with the height

4 0

3 years ago