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3 years ago

5

Kevin wants to make a mixture that is 50% lemon juice and 50% lime juice. How much 100% lemon juice should he add to a juice mix

ture that is 40% lemon juice and 60% lime juice to make 6 gal of the 50% lemon/50% lime juice mixture?

1 answer:

saveliy_v [14]3 years ago

6 0

In order to solve this, I need to know the volume of the 50% lemon juice 50% lime juice mixture.

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t = -48/(2(-16)) = 1.5

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John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches

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a) The probability that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is 0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show = 0.7 ⇒ P(J) = 0.7

Probability that Jane watches a certain show = 0.3 ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

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a. ) Here, we need to find the probability of both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

$P(J/Je) = \frac{P(J \cap Je)}{P(Je)}$

$\implies 0.4 = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3 = 0.12$

Hence the probability that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

$P(Je/J) = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J) = \frac{0.12}{0.7} = 0.1714$

Hence, the probability that Jane watches the show, given that John does is 0.1714.

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So, the probability of both of them seeing the show TOGETHER is 0.12.

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