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kondaur [170]
3 years ago
8

A circuit contains three resistors connected in parallel. The value of R1 is 2 K , the value or R2 is 6 K , and the value of R3

is 10 K . If the supplied voltage is 100 VDC, what is the total power in the circuit?
A. 2.18 W

B. 8.18 W

C. 7.67 W

D. 4.24 W

(Can someone help me understand how to get the answer?)
Physics
1 answer:
Murljashka [212]3 years ago
4 0
<h2>Answer: C. 7.67 W </h2>

Explanation:

Firstly, we are told the three resistors are <u>connected in parallel</u>, this means we have to use the following equation to find the total resistance R of the circuit:

\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}  (1)

Where: R_{1}=2k\Omega, R_{2}=6k\Omega, R_{3}=10k\Omega

Solving (1):

\frac{1}{R}=\frac{1}{2k\Omega}+\frac{1}{6k\Omega}+\frac{1}{10k\Omega}  (2)

\frac{1}{R}=\frac{23}{30k\Omega}  (3)

R=1.3043k\Omega}=1304.34\Omega  (4)  This is the total resistance of the circuit

On the other hand, the total power P of this circuit is given by the following equation:

P=\frac{V^{2}}{R}   (5)

Where V=100V is the total voltage of the circuit.

Solving:

P=\frac{(100V)^{2}}{1304.34\Omega}   (6)

Finally:

P=7.67V\Omega=7.67W   (7) This is the total power of the circuit in Watts (W)

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