<u>Answer:</u>
The older repear will harvest in 6 hrs
<u>Explanation:</u>
Given a field can be harvested in 1 hr with 2 reapers
Consider the total field to be 1
Let x be the time of older’s reaper
The field can be harvested in 1.2 hr with newer reaper alone
Older’s time of harvesting =
per hour
Newer’s time of harvesting =
per hour
Total (Older+Newer) = 1 =
}


1.2 + x = 1.2x
1.2 = 0.2x
x = 6
Therefore, older repear will harvest in 6 hrs
Answer: 5.125.
Step-by-step explanation: (1 / 4) + (6 / 8) + 2 + (5 / 8) + (6 / 4) = 5.125.
Hope I helped you.
You are solving for x, correct?
Answer:
Maximum: 7
Minimum: 0
Step-by-step explanation:
A proper subset B of a set C, denoted
, is a subset that is strictly contained in C and so necessarily excludes at least one member of C.
This means that the number of elements in B must be at least 1 less than the number of elements in C. If the number of elements in C is 8, then the maximum number of elements in B can be 7.
The empty set is a proper subset of any nonempty set. Hence, the minimum number of elements in B can be 0.
Answer:
D. No balance transfer fee
Step-by-step explanation:
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