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neonofarm [45]
3 years ago
8

Solve for x using the quadratic formula x^2-6x +9=0

Mathematics
2 answers:
hram777 [196]3 years ago
7 0

Answer:

The value of X is 3

Step-by-step explanation:

x²-6x+9=0

x²- 3x - 3x + 9= 0

X(x-3) -3(x-3)=0

(x-3) (x-3)=0

(x-3)²=0

(x-3)=0

x-3 = 0

X= 3

Rufina [12.5K]3 years ago
4 0

Answer:

3 both ways x = 3

EXPLANATION:

plug in inputs and do a little simplifying we get

x = 6 ± √(36-36) all of that over 2

So we simplify and we get 6±sqrt(0) / 2

Then we get 6/2 = 3

x-0 = x+0

thats why there is only one answer

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A triangle has sides with length of 5 yards,14 yards,and 16 yards.is it a right triangle
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Answer:

As the largest side is  

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Step-by-step explanation:

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(1 point) Linear System - Three Variables Solve the following system of equations using Gaussian elimination method. If there ar
EastWind [94]

Answer:

x=\frac{-363}{70} ≈ -5.1857

y=\frac{-192}{35} ≈ -5.4857

z=\frac{313}{84} ≈ 3.7262

Step-by-step explanation:

Rewrite the equation system as:

6x+8y=-75

-3x+6y+6z=5

2x-9y=39

Now, write the system in its augmented matrix form:

\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]

applying row reduction process to  its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]

R3+2R1

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]

3R2+2R1

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]

15R3+20R2

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]

Now we have a simplified system:

-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565

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From (3):

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Replacing (4) in (2)

y=\frac{-192}{35} (5)

Finally replacing (5) and (4) in (1)

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Answer:

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Step-by-step explanation:

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