Question

The coordinates of the vertices of AJKL are J(0, 2), K(3, 1), and L(1, – 5).

Answer 1

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Answer:

• JK slope: -1/3
• KL slope: 3
• JL slope: -7
• is
• two of the slopes have a product of -1

Step-by-step explanation:

The slope formula is useful.

  m = (y2 -y1)/(x2 -x1)

__

JK slope = (1 -2)/(3 -1) = -1/3

KL slope = (-5-1)/(1-3) = -6/-2 = 3

JL slope = (-5-2)/(1-0) = -7

We observe that slopes (-1/3) and (3) have a product of -1, so those line segments are perpendicular. The triangle is a right triangle.