The coordinates of the vertices of AJKL are J(0, 2), K(3, 1), and L(1, – 5).
1 answer:
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Answer:
- JK slope: -1/3
- KL slope: 3
- JL slope: -7
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- two of the slopes have a product of -1
Step-by-step explanation:
The slope formula is useful.
m = (y2 -y1)/(x2 -x1)
__
JK slope = (1 -2)/(3 -1) = -1/3
KL slope = (-5-1)/(1-3) = -6/-2 = 3
JL slope = (-5-2)/(1-0) = -7
We observe that slopes (-1/3) and (3) have a product of -1, so those line segments are perpendicular. The triangle is a right triangle.
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