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Serjik [45]
3 years ago
7

4) Which of the following events can change the

Chemistry
1 answer:
Phantasy [73]3 years ago
6 0

Answer: Option D) All of the above.

Explanation:

The ecosystem is made up of living and non-living component relating with their environment. i.e in an ecosystem, plants and animals relate with the food nutrients, climate and weather conditions, soil structure etc

Thus, all of the conditions: a rise in temperature; natural disaster like flooding; the introduction of a new animal species like a predator will definitely change the previously stable condition of an ecosystem.

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kozerog [31]
The answer is 78 mph

6 0
3 years ago
Read 2 more answers
What is the freezing point of a solution of 0.5 mol of LiBr in 500 mL of water? (Kf = 1.86°C/m) –1.86°C –7.44°C –5.58°C –3.72°C
tresset_1 [31]

Answer:

  • Last choice: <em><u>- 3.72°C</u></em>

Explanation:

The freezing point depression in a solvent is a colligative property: it depends on the number of solute particles.

The equation to predict the freezing point depression in a solvent is:

  • ΔTf = Kf × m × i

Where,

  • ΔTf is the freezing point depression of the solvent,
  • m is the molality,
  • Kf is the cryoscopic molal constant of the solvent, and i is the Van'f Hoff factor, which is the number of ions produced by each unit formula of the ionic compound.

The calcualtions are in the attached pdf file. Please, open it by clicking on the image of the file.

Download pdf
6 0
3 years ago
No Spam!!!! PLEASE HURRY!!! What is the base name for the following compound?<br><br> C-C-OH
notsponge [240]

Answer:

hydroxide, I think

Explanation:

7 0
3 years ago
please help me please
Musya8 [376]

Answer:

Two advantages are: Its cheap and it is a renewable energy source. Two disadvantages are it's not windy everyday and it will take up a lot of space for windmills.

Explanation:

4 0
3 years ago
Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc
wolverine [178]

Answer:

(1) 2Al(s) + 2NaOH(aq) + 6H2O(l) ↔2Na[Al(OH)4](aq) + 3H2(g)

∴ Kc = ( PH2³ * [Na[Al(OH)4]² ) / [NaOH]² = 11

(2) H2O(l) + SO3(g) ↔ H2SO4(aq)

∴ Kc = [ H2SO4 ] / PSO3 = 0.0123

(3) 2P4(s) + 6O2(g) ↔ 2P4O6(s)

∴ Kc = Kc = 1 / PO2∧6

Explanation:

(1) 2Al(s) + 2NaOH(aq) + 6H2O(l) ↔ 2Na[Al(OH)4](aq) + 3H2(g)

∴ O /  Al: 0 → +2 ≡ 2e-

         Na: +1 → +2

∴ R /  H: +1 → 0

     2 - Al - 2

     2 - Na - 1

     8 - O - 8

     14 - H - 14

⇒ Kc = ( PH2³ * [Na[Al(OH)4]² ) / [NaOH]² = 11

(2) H2O(l) + SO3(g) ↔ H2SO4(aq)

           1 - S - 1

           4 - O - 4

           2 - H - 2

⇒ Kc = [ H2SO4 ] / PSO3 = 0.0123

(3) 2P4(s) + 6O2(g) ↔ 2P4O6(s)

       8 - P - 8

       12 - O - 12

⇒ Kc = 1 / PO2∧6

6 0
3 years ago
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