Answer:
-152.92°C
Explanation:
Initial volume = 0.750 mL
Initial temperature = -32.7 °C (-32.7 + 273.15 K = 240.45 k)
Final temperature = ?
Final volume = 0.750 mL / 2= 0.375 mL
Solution:
The given problem will be solve through the Charles Law.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂ / V₁
T₂ = 240.45 k × 0.375 mL / 0.750 mL
T₂ = 90.17 mL.K / 0.750 mL
T₂ = 120.23 K
Temperature in celsius:
120.23 K - 273.15 = -152.92°C
Answer:
Here are the equations for those reactions:
copper oxide + sulfuric acid → copper sulfate + water
CuO + H2SO4 → CuSO4 + H2O
copper carbonate + sulfuric acid → copper sulfate + water + carbon dioxide
CuCO3 + H2SO4 → CuSO4 + H2O + CO2
Copper oxide and copper carbonate are insoluble, so usually you add an excess (more than enough to react with all the acid) then filter the mixture. The excess solid stays in the filter paper as a residue. The copper sulfate solution drips through as a filtrate. This can be warmed to evaporate the water, leaving copper sulfate crystals behind.
Explanation:
Please see the pic, I'd solved in it..
Broo whenever it sounds cool