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3 years ago

I need help ASAP I don’t know what to do

Chemistry

1 answer:

rodikova [14]3 years ago

7 0

Answer:

i cant see it

Explanation:

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The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If

Hatshy [7]

$7.7 \times 10^{2} \; \text{K}$ .

<h3>Explanation</h3>

Units of each quantity:

P = 28 atm;
V = 0.045 L;
n = 0.020 mol;

Ideal gas constant:

$R = 0.0820573 \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}$ .

Apply the ideal gas law:

$T = \dfrac{P \cdot V}{n \cdot R} = \dfrac{{\bf 28} \; \text{atm} \times {\bf 0.045} \;\text{L} }{{\bf 0.020}\; \text{mol} \times {\bf 0.0820573} \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}} = {\bf 767.76} \; \text{K}$ .

All data given in this question come with two significant figures. Round the value of T to two significant figures:

$T = 767.76 \;\text{K} = 7.7 \times 10^{2} \; \text{K}$ .

7 0

3 years ago

Read 2 more answers

This is due at 12am HELP!!

Lisa [10]

Answer:

I have the same

Explanation:

like I have the same homework as you are u in my class lol?

4 0

3 years ago

What are the three parts of nucleotide

Yuri [45]

Answer:

The three parts of the nucleotide building block of DNA are the sugar, the base and the phosphate.

Explanation:

Hope that helps!

6 0

3 years ago

Read 2 more answers

Number of miles of Xe in 12.00g of Xe

Korvikt [17]

1 mol of Xe has a mass of 131 grams
x mol of Xe has a mass of 12 grams.

1/x = 131/12 Set up proportion from the information above. Cross multiply
131x = 12 Divide by 13`
x = 12/131
x = 0.0916 mol <<<< ====

Just for fun
I don't know if a calculator would even tell me the number of miles in 12 grams of Xe

The diameter is 216 * 10^-12 meters. Maybe.
1 mol of anything is 6.02 * 10^23
0.0912 mols contain x atoms

1/0.0912 = 6.02 * 10^23 / x
x = 0.0912 * 6.02 * 10^23
x = 5.49 * 10 ^ 22 This thing is going to stretch out quite a ways.

1 atom = 312 * 10^- 12 meters.
5.049 * 10^22 = x meters.
x = 312 * 10^-12 * 5.49 * 10^22
x = 1.7 * 10 ^10 km = 1.07 * 10 ^10 miles We're talking about beyond Pluto.

I'm sorry I should delete this. If you want to you can. Take my answer for the number of mols. It's likely correct.

5 0

4 years ago

What is the final volume, in milliliters, when 5.80 mL of 25.0 %(m/v) NaOH solution is diluted to give a 3.50 %(m/v) NaOH soluti

Zigmanuir [339]

Answer:

41.43 mL

Explanation:

First we calculate the mass of NaOH in the original solution:

25.0 % m/v means that in 100 mL of solution, there are 25 grams of NaOH.

This means that in 5.80 mL, we would have (5.80 * 25/100) 1.45 grams of NaOH.

Then we calculate the volume of the diluted solution, using the grams of NaOH (that remain the same throughout the dilution process):

1.45 g NaOH * $\frac{100 mL}{3.50gNaOH}$ = 41.43 mL

7 0

3 years ago