Hey there!
2/3 = a/30
First: you have to CROSS MULTIPLY the given numbers
2(30) = 3(a)
2(30) = 60
3(a) = 3a
New EQUATION: 3a = 60
Second: DIVIDE 3 to BOTH SIDES
3a/3 = 60/3
CANCEL out: 3/3 because that gives you 1
KEEP: 60/3 because that helps you solve for your a-value
60/3 = a
60/3 = 20
Therefore, your answer is: a = 20
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
let y = x^2
4y^2 -21y + 20 = 0
solve for y
then substitute back in to get x
Answer:
(27.3692 ; 44.6308)
Step-by-step explanation:
Mean, xbar = 36
Standard deviation, s = 11
Sample size, n = 12
Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/sqrt(n)
Margin of Error = 2.718 * 11/sqrt(12) = 8.6308
Confidence interval :
Lower boundary : 36 - 8.6308 = 27.3692
Upper boundary : 36 + 8.6308 = 44.6308
(27.3692 ; 44.6308)
1.To find the triangle area is base x height : 4.33 x 5=21.65
Perimeter : 5+5+5=15
2. 6•3=18+(3•2)=18+6=24=area
16=perimeter
3. Not sure
4. 12•17=204=area
Perimeter : 13+17+17=47
Hoped I helped!
