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Ostrovityanka [42]
3 years ago
6

Eggs were $2.05 per dozen on January 1st and $2.00 per dozen February 1st what percent did the price decrease during January?

Mathematics
2 answers:
Sholpan [36]3 years ago
8 0
This is a 2.5% decrease in price.
Murrr4er [49]3 years ago
7 0
For this case we can make the following rule of three:
 2.05 $ -----> 100%
 2.00 $ -----> x
 Clearing x we have:
 x = (2.00 / 2.05) * (100)
 x = 97.5
 Then, the percentage that decreases is:
 100-97.5 = 2.5%
 Answer:
 
the price did decrease 2.5% during January
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3 years ago
The function g(x) = 8x2 – 48x + 65 written in vertex form is g(x) = 8(x – 3)2 – 7. What is the vertex of g(x)?
maksim [4K]
The answer is (3, -7). If the function is written in the form y = a(x – h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 – 48x + 65 in the form of a(x – h)^2 + k. g(x) = 8x^2 – 48x + 65. g(x) = 8x^2 – 48x + 72 - 72 + 65. g(x) = (8x^2 – 48x + 72) - 7. g(x) = (8 * x^2 – 8 * 6x + 8 * 9) - 7. g(x) = 8(x^2 - 6x + 9) - 7. g(x) = 8(x - 3)^2 - 7. The function is now in the form a(x – h)^2 + k, where a = 8, h = 3, and k = -7. Thus, the vertex is (3, -7).
4 0
3 years ago
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The wind blew away 30 of your muffins.that was 5/6 of all of them! With how many did you start with .
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Which linear system of equations does the matrix represent 4 -7 -14 4 -12 4
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The given matrix represent the following linear system

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3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

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3 years ago
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