The answer is (3, -7). If the function is written in the form y = a(x –
h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 – 48x
+ 65 in the form of a(x – h)^2 + k. g(x) = 8x^2 – 48x + 65. g(x) = 8x^2
– 48x + 72 - 72 + 65. g(x) = (8x^2 – 48x + 72) - 7. g(x) = (8 * x^2 – 8
* 6x + 8 * 9) - 7. g(x) = 8(x^2 - 6x + 9) - 7. g(x) = 8(x - 3)^2 - 7.
The function is now in the form a(x – h)^2 + k, where a = 8, h = 3, and k
= -7. Thus, the vertex is (3, -7).
5/6 x = 30
x = 30 ÷ 5/6
x = 36 <=== muffins you start with
The given matrix represent the following linear system
4x - 7y = -12
-14x + 4y = 4
Good luck!!!
The equation of the hyperbola is : 
The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)
As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin:
The distance from center to focus is 'c' and here focus is at (-50,0)
So, c= 50
Now if the distance from center to the directrix line is 'd', then

Here the directrix line is given as : x= 2304/50
Thus, 
⇒ 
⇒ a² = 2304
⇒ a = √2304 = 48
For hyperbola, b² = c² - a²
⇒ b² = 50² - 48² (By plugging c=50 and a = 48)
⇒ b² = 2500 - 2304
⇒ b² = 196
⇒ b = √196 = 14
So, the equation of the hyperbola is : 