All categories

3 years ago

Pls help me pls i need help :)

Mathematics

1 answer:

goldenfox [79]3 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

How do I do number 29?

Oksi-84 [34.3K]

-2x+ 12 = x^2 +16
-2x -4 = x^2
-4= x^2 + 2x
-4= 3x
-4/3 = 3/3x
-1.333 (repeated) = x

4 0

2 years ago

natta225 [31]

Answer:

d. ∆UVW ∼ ∆UWT ∼ ∆WVT

Step-by-step explanation:

Two triangles are similar if the corresponding angle are congruent and if the ratio of the corresponding sides are proportional.

The logic is in three scenarios. The Cases that lead to similarities in a triangle can be expressed as follows

i. If two sides of a triangle are in the same ratio to the corresponding side of another triangle and the included angle are the same.

ii. If the three corresponding sides are in the same ratio then the triangles are similar.

iii. Also if the angles are of a triangle is congruent to the corresponding angles of another triangles they are similar.

6 0

2 years ago

A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the prob

UkoKoshka [18]

Answer:

The probability that 8 mice are required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

$P(X=r)=^nC_r p^rq^{n-r}$

Where, p is the probability of success $p=\frac{2}{7}$

q is the probability of failure q=1-p, $q=1-\frac{2}{7}=\frac{5}{7}$

n is total number of trials n=8

r=3

Substitute the values,

$P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}$

$P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}$

$P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}$

$P(X=3)=0.2428$

Therefore, the probability that 8 mice are required is 0.2428.

5 0

3 years ago

What is the factored form of 6n4 – 24n3 + 18n?

seropon [69]

Answer: Its factored form will be

$6n(n-1)(n^2-3n-3)$

Step-by-step explanation:

Since we have given that

$6n^4-24n^3+18n$

So, we need to factor ,

$6n(n^3-4n^2+3)$

Now,

$\text{Let }p(n)=n^3-4n^2+3$

Now, by hit and trial method, we put n=1,

$p(1)=1^3-4\times1^2+3=1-4+3=1-1=0$

$n=1\\n-1=0$

So, n-1 is also factor of p(n).

Now,

$\frac{n^3-4n^2+3}{n-1}=n^2-3n-3$

So, its factored form will be

$6n(n-1)(n^2-3n-3)$

8 0

3 years ago

Read 2 more answers

This statement is justified by which property of equality?

Galina-37 [17]

Answer:

symmetric property

Step-by-step explanation:

with symmetric property if x=y then both values on either side of the equal sign will be equal

4 0

2 years ago