The value of h(t) when 
is 10.02.
Solution:
Given function 
To find the value of h(t) when :
Substitute in the given function.
Now multiply the common terms into inside the bracket.
Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.
To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64
= 10.02
Hence the value of h(t) when is 10.02.
You can use the identity
cos(x)² +sin(x)² = 1
to find sin(x) from cos(x) or vice versa.
(1/4)² +sin(x)² = 1
sin(x)² = 1 - 1/16
sin(x) = ±(√15)/4
Then the tangent can be computed as the ratio of sine to cosine.
tan(x) = sin(x)/cos(x) = (±(√15)/4)/(1/4)
tan(x) = ±√15
There are two possible answers.
In the first quadrant:
sin(x) = (√15)/4
tan(x) = √15
In the fourth quadrant:
sin(x) = -(√15)/4
tan(x) = -√15
To get the equivalent fractions, you simply have to multiply
the fraction with another fraction that would equal to 1.
2/8 x 2/2 (this is equal to 1) = 4/16; 1/4
3/8 x 2/2 = 6/16; 9/24
4/8 x 2/2 = 8/16; 1/2
12 : 21 → (divide by 3) → 4 : 7
Answer: 4
Answer:
1 * -2, 7 - 9, and 2^2 - 2 * 3
