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taurus [48]
4 years ago
6

10 seconds into a race, Clara was at the 25 meter mark. At 60 seconds into the race, she was at the 100 meter mark. What was the

approximate rate of change in Clara's speed between 10 seconds and 60 seconds? A) .6 meters per second B) 1.5 meters per second C) 2 meters per second D) 7.5 meters per second
Mathematics
2 answers:
Alla [95]4 years ago
8 0

Answer:

B) 1.5 meters per second

Step-by-step explanation:

The rate of change in Clara's speed between 10 and 60 seconds can be calculate as:

Speed =\frac{X_f-X_i}{t_f - t_i}

Where X_f is the mark at 60 seconds, X_i is the mark at10 seconds,   t_f is the 60 seconds and t_i is 10 seconds.

Replacing values, we get:

speed =\frac{100 meters- 25 meters}{60 second-10 second } =1.5 meters per second

So, the speed between 10 and 60 seconds is 1.5 meters per second

ycow [4]4 years ago
7 0
B is the correct answer
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8 0
3 years ago
Giant is selling Cereal at $8 for 3 boxes.what is the cost per box?
Zolol [24]

Answer:

$2.67

Step-by-step explanation:

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7 0
3 years ago
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Lucy was running a 10 mile race and the graph represents her running pace for the race. If the x-axis represents miles ran and t
Ostrovityanka [42]

Answer:

C

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Have a great day!

4 0
3 years ago
Let f(x)=4x+7 and g(x)=3x-5. Find (g o f)(-4)<br><br> A)-32<br> B)-61<br> C)-64<br> D)-9
olya-2409 [2.1K]

Answer for this question is -32

5 0
3 years ago
Total profit P is defined as total revenue R minus total cost​ C, and is given by the function P(x)=R(x)−C(x). Find the total pr
satela [25.4K]

Given:

The revenue function is

R(x)=126.98x-0.5x^2

The cost function is

C(x)=3809.40+0.7x^2

To find:

The profit function.

Solution:

We know that, the total profit P is defined as total revenue R minus total cost​ C.

So, the profit function is

P(x)=R(x)-C(x)

P(x)=126.98x-0.5x^2-(3809.40+0.7x^2)

P(x)=126.98x-0.5x^2-3809.40-0.7x^2

P(x)=-3682.42-1.2x^2

Therefore, the profit function is P(x)=-3682.42-1.2x^2.

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