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4 years ago

Find two numbers whose sum is 0 and who's difference is 8

Mathematics

2 answers:

timofeeve [1]4 years ago

6 0

4 and -4 (in that order specifically)

4 + -4 = 4 - 4 = 0
4 - -4 = 4 + 4 = 8

dalvyx [7]4 years ago

3 0

Sum and Difference of Numbers

The two numbers are +4 and -4 whose sum is 0 and difference is 8

Step-by-step explanation:

Let the two numbers be x and y .

Then

x + y = 0; ------- (1)

and

x - y = 8; ------- (2)

Adding the two equation,

x + y = 0;

x - y = 8;

------------

2 × x = 8

⇒ x = 8/2

⇒ x = +4

Subtracting (2) from (1)

⇒ 2 × y = -8

⇒ y = -4

Hence, the two numbers are +4 and -4 whose sum is 0 and difference is 8

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One side of a triangle is twice the shortest side. The third side is five feet more than the shortest side. The perimeter is 17

guajiro [1.7K]

Answer:

3, 6 and 8

Step-by-step explanation:

In order to solve the problem, we call:

$a$ = length of the 1st side of the triangle

$b$ = length of the 2nd side of the triangle

$c$ = length of the 3rd side of the triangle

From the text of the question, we know that:

- One side of a triangle is twice the shortest side --> we can write this as

$b=2a$ (1) (assuming "a" is the shortest side)

- The third side is five feet more than the shortest side. -->

$c=a+5$ (2)

- The perimeter is 17 feet -->

$a+b+c=17$ (3)

So now we have 3 equations with 3 unknown variables. Substituting (1) and (2) into (3) we can find the value of "a", the shortest side:

$a+2a+a+5=17\\4a=17-5=12\\a=3$

And so

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