Find two numbers whose sum is 0 and who's difference is 8
2 answers:
4 and -4 (in that order specifically)
4 + -4 = 4 - 4 = 0
4 - -4 = 4 + 4 = 8
Sum and Difference of Numbers
The two numbers are +4 and -4 whose sum is 0 and difference is 8
Step-by-step explanation:
Let the two numbers be x and y .
Then
x + y = 0; ------- (1)
and
x - y = 8; ------- (2)
Adding the two equation,
x + y = 0;
x - y = 8;
------------
2 × x = 8
⇒ x = 8/2
⇒ x = +4
Subtracting (2) from (1)
⇒ 2 × y = -8
⇒ y = -4
Hence, the two numbers are +4 and -4 whose sum is 0 and difference is 8
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−7w+8(w+1)=w−7
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No solutions.
Answer:233
Step-by-step explanation:cause i said so
Answer:
third side is 4
Step-by-step explanation:
using Pythagoras theorem,
(√33)² + l² = 7²
33 + l² = 49
l² = 49 - 33
l² = 16
l = √16
l = 4
A because you just distribute the 12 to both