We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
im not sure but i think its -25
Step-by-step explanation:
hope im not wrong:)
hope you have a great day and god loves you:))
You are suppose to use a ruler to rotate the thing you need to rotate
Answer:
1. B>-7 2. M is > or = to 8.8 3. Y < 1/2
Step-by-step explanation:
We have that
[√(2x+1)]+3=0
for x=4
[√(2*4+1)]+3=0
[√(9)]+3=0
3+3=0----------6 is not zero
therefore
the solution is not correct for x=4
[√(2x+1)]+3=0--------> [√(2x+1)]=-3---------> <span>There is no real solution for that equation
</span>Because (2x+1) >= 0
the solution is with complex numbers
