Hello,
1) Verify if it is a 2 degree.
2) y=ax²+bx+c
Calulate a,b,c by Gauss's methode
a=3, b=0,c=-1
y=3x²-1
Answer:
smaller (t) = 2 and this in coordinates form (2,0)
larger (t) = 15 and this in coordinates form (15,0)
the vertex of the parabola = or in decimals (8.5, 42.25)
Step-by-step explanation:
- For the zeros of the function take each bracket and make it equal to zero.
SMALLER (t):
(t-2)=0
(add 2 for both sides)
t=2
LARGER (t):
(t-15)=0
(add 15 for both sides)
t=15
- For the vertex of the parabola you do:
step1: expand the brackets:
f(t)=-(t-2)(t-15)
f(t)=
step2: define a,b and c using the expression :
a= -1 (the coefficient of )
b= 17 (the coefficient of t)
c= -30 (the single number without a letter)
step3: sub the values in the formula to find the x coordinate of the vertex :
=
= or in decimals 8.5
step4: sub the value of t (the x-coordinate) in equation f(t):
f(t)=
f ( ) = - + 17× - 30
= + -30
= or in decimals 42.25
(THIS IS A PICTURE OF THE GRAPH↓)
It would be in the ten thousands place.
Answer:
144%
Step-by-step explanation:
We are told that Linnea's company's revenue in 2017 is 36/25 of its revenue in 2016..
To find the Linnea's company's revenue in 2017 as a percent of its revenue in 2016, we will have to figure out 36 is what percent of 25.
Therefore, Linnea's company's revenue in 2017 is 144% of its revenue in 2017.
Step-by-step explanation:
Given \:number (m) = £ 490Givennumber(m)=£490
Increase (g) = 11\%Increase(g)=11%
\begin{gathered} \red{ Required \:number } \\= m\Big( \frac{(100+g)}{100} \Big)\\= 490\Big(\frac{100+11}{100}\Big)\\= 490 \times \frac{111}{100} \\= 490 \times 1.11 \\= £ 543.9 \end{gathered}
Requirednumber
=m(
100
(100+g)
)
=490(
100
100+11
)
=490×
100
111
=490×1.11
=£543.9
Therefore.,
\red{ Required \:number }\green { = £ 543.9}Requirednumber=£543.9
•••♪