<h3><u>Solution</u></h3>
<u>Given </u><u>:</u><u>-</u>
- Perimeter of rectangle = 72 cm
- The length is 3 more than twice the width.
<u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u>
<h3 /><h3>
<u>Explantion</u></h3>
<u>Using </u><u>Formula</u>

<u>Let,</u>
- Length of Rectangle = x cm
- Breadth of Rectangle = y cm
<u>According</u><u> to</u><u> question</u><u>,</u>
==> perimeter of Rectangle = 72
==> 2(x+y) = 72
==> x + y = 72/2
==> x + y = 36_________________(1)
<u>Again,</u>
==> x = 2y + 3
==> x - 2y = 3__________________(2)
<u>Subtract</u><u> </u><u>equ(</u><u>1</u><u>)</u><u> </u><u>&</u><u> </u><u>equ(</u><u>2</u><u>)</u>
==> y + 2y = 36 - 3
==> 3y = 33
==> y = 33/3
==> y = 11
<u>keep </u><u>in </u><u>equ(</u><u>1</u><u>)</u>
==> x - 2×11 = 3
==> x = 3 + 22
==> x = 25
<h3><u>Hence</u></h3>
- <u>Length</u><u> of</u><u> </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u> </u><u>cm</u>
- <u>Width </u><u>of </u><u>Rectangle</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u> </u><u>cm</u>
<h3>
<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h3>
<h3 />
Answer:
Brother is 70.5 and sister is 64.5
Step-by-step explanation:
you will need to set up a simple equation and give out variables.
Girls age = 6-x
Brother's age= x
the you will take those 2 and add them and place them equal to 135:
6-x+x=135
6-2x+6=135+6
The 6 cancels out
2x=141
2x/2=141/2
x=70.5
The brother's age would be 70.5 then and the girl's would be 64.5
(93+67+78+44+123)/5=405/5=81 pizzas per day on average
C is your answer.
Hey there!!
Let us take the first number as ' x '
According to the question
The second number exceeds the first number by 15
hence, the second number = x+15
The sum of both the numbers = 69
which means
x + x + 15 = 69
2x+15 = 69
Subtracting by 15 on both sides
2x + 15 - 15 = 69 - 15
2x = 54
dividing by 2 on both sides
x = 27
first number = 27
second number = 27 + 15
= 42
Hope my answer helps!