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Andreyy89
3 years ago
14

Air resistance is a type of a. motion. b. acceleration. c. velocity. d. friction.

Physics
2 answers:
Brilliant_brown [7]3 years ago
7 0
Friction as it opposite the direction of motion 
Alex73 [517]3 years ago
3 0
Air resistance is a type of friction.

Hope this helps! :D
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6. What is Mass????????????????
maria [59]
Mass is a measure of the amount of matter in an object !!
hope this helpeddd (:
8 0
3 years ago
تقطع اولا مسافة 8 km شمالا من البيت ثم تمشي شرقا حتى تكون ازاحتك من البيت 10km ما مقدار المسافة التي قطعتها شرقا
Natali [406]
He moved 2 km
I speak arabik ;)

8 0
3 years ago
A 3.00 m-long 6.00-kg ladder pivoted at the top hangs down from a platform at the circus. A 42.0-kg trapeze artist climbs to a p
statuscvo [17]

Answer:

The period of the system of ladder and woman, T = 2.5 seconds

Explanation:

Mass of the ladder, m_1 = 6 kg

Mass of the artiste, m_2 = 42.0 kg

Length of the ladder, L = 42.0 kg

The total moment of inertia can be calculated using the equation:

I = \frac{1}{3} M_1 L^2 + m_2 (\frac{L}{2} )^2\\I = \frac{1}{3} *6*3^2 + 42* (\frac{3}{2} )^2\\I = 18 + 94.5\\I = 112.5 kg m^2

D = L/2 = 3/2

D = 1.5 m

The frequency of the system of ladder and woman follows that of a physical pendulum which can be given by the equation:

f = \frac{1}{2\pi } \sqrt{\frac{mgD}{I} } \\f = \frac{1}{2\pi } \sqrt{\frac{48*9.8*1.5}{112.5} }\\f = 0.4

The period of the system of ladder and woman is given by:

T = 1/f

T = 1/0.4

T = 2.5 seconds

5 0
3 years ago
What are the approximate dimensions of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 27
gayaneshka [121]

Answer:

   s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

                   θ = 1.22 λ / D

where you lick the wavelength and D the mediator of the circular aperture.

In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values ​​into the formula

                 

λ = 400 nm      θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm     θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

          θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm       s_400 = θ R

                         S_400 = 6 10⁻⁵ 275 10³

                         s_400 = 16.5 m

λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

                          s_700 = 29.4 m

8 0
4 years ago
a couple has just learned that their daughter has hemophilia. They already have a son who does not have the disease. What are th
Step2247 [10]

Answer: The genotypes of the couple are- XᵇX and XᵇY, where Xᵇ denotes the X chromosome having gene for hemophilia.

Hemophilia is a X linked recessive disorder, which means that the gene for hemophilia is carried by X chromosome. A female individual will be affected by the disorder if she carries two copies of the gene causing hemophilia. A male ( XY) will be hemophilic when his X chromosome bears the gene for hemophilia.

As per the information given in the question, son is not having the disease, which means that he has inherited normal X chromosome from his mother. On the other hand, daughter is hemophilic, which indicates that she has inherited both the X chromosomes with hemophilic gene that is XᵇXᵇ ( one X from father and other from mother).

This condition is only possible when the male parent is affected and female parent is carrier for the disease.

Thus, the genotypes of the couple are- XᵇX and XᵇY, where Xᵇ denotes the X chromosome having gene for hemophilia.

3 0
4 years ago
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