What happens to an isotope that undergoes alpha decay
1 answer:
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Answer:
Answer is
A. I = 6.3×10^8 A
B. Yes
C. No
Refer below.
Explanation:
Refer to the picture for brief explanation.
Answer:
LED bulb = 0.145 A
Incandescent bulb = 0.909 A
CFL bulb = 0.218 A
Explanation:
Given:
Power rating of LED bulb (P₁) = 16 W
Power rating of incandescent bulb (P₂) = 100 W
Power rating of CFL bulb (P₃) = 24 W
Terminal voltage across the circuit (V) = 110 V
We know that, power is related to terminal voltage and current drawn as:
Express this in terms of 'I'. This gives,
Now, calculate the current drawn in each bulb using their respective values.
For LED bulb,
So, current drawn is given as:
For incandescent bulb,
So, current drawn is given as:
For CFL bulb,
So, current drawn is given as:
Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.