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kolbaska11 [484]
3 years ago
15

What happens to an isotope that undergoes alpha decay

Physics
1 answer:
Gelneren [198K]3 years ago
3 0

When an isotope undergoes an alpha decay it means it has too many protons. The nucleus releases the alpha particle and energy.

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A truck skids for a distance of 25 m with the road pushing on its tires with force of 1500 N as its brakes
MakcuM [25]

Answer:-6800J

Explanation: 8.0m x 850N = 6800

Rewritten as a negative when brake/stop -6800

6 0
3 years ago
Read 2 more answers
A box has a mass of 150kg and the surface area of the bottom of the box is :
charle [14.2K]

Answer:

Pressure = 100 Pascals

Explanation:

pressure =  \frac{force}{area}  \\  =  \frac{150 \times 10}{15}  \\  =  \frac{1500}{15}  \\  = 100 pa

3 0
3 years ago
Monochromatic light is incident on a metal surface, and electrons are ejected. If the intensity of the light increases, what wil
drek231 [11]

Answer:The rate of ejection of photoelectrons will increase

Explanation:

If the frequency of incident monochromatic light is held constant and its intensity is increased, the rate of ejection of photoelectrons from the metal surface increases with increase in intensity of the monochromatic light. More current flows due to more ejection of photoelectrons.

4 0
3 years ago
What type of relationship exists between the length of a wire and the resistance, if all other factors remain the same? A. Resis
ZanzabumX [31]
<h3>Answer</h3>

(A) Resistance is directly related to length.

<h3>Explanation</h3>

Formula for resistance

R = p(length) / A

where R = resistance

           p = resistivity(material of wire)

           A = cross sectional area

So it can be seen that resistance depends upon 3 factors that are length of wire , resistivity of wire and the cross sectional area of the wire.

If two of the factors, resistivity and cross sectional area, are kept constant then the resistance is directly proportional to the length of wire.

<h3> R ∝ length</h3>

This means that the resistance of the wire increases with the increase in length of the wire and decreases with the decrease of length of the wire.

5 0
3 years ago
Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magni
joja [24]

Answer:

Explanation:

Use the following equation:

E=\frac{q}{F} and solve for F:

F=\frac{q}{E} and filling in:

F=\frac{.0600}{1500}

F = 4.0 × 10^{-4 N

3 0
3 years ago
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