Answer:
The last option is correct
ΔT1 = 4 sec ΔT2 = 4 sec ΔT3 = 4 sec
S = V0 t + 1/2 a t^2
S1 = 1/2 a t^2 = 8 a where V0 is the speed at the start of the interval
During any interval (of 4 sec) the particle travels 1/2 a t^2 = 8 a due to its acceleration - and you need to include the speed at the start of the interval
S1 = 8a
S2 = 8 a + 8 a = 16 a
S3 = 16 a + 8 a = 24 a
Note: V2 = V1 + a t for any interval
V2 - V1 = V1 + a t - V1 = a t
and a = (V2 - V1) / t = a the speed increase is constant during the interval
The answer fam is <span>stratosphere,Thermosphere,mesosphere </span>
By Newton's second law, the net force on the object is
∑ <em>F</em> = <em>T</em> - <em>mg</em> = - <em>ma</em>
where
• <em>T</em> = 25 N, the tension in the string
• <em>m</em> is the mass of the object
• <em>g</em> = 9.8 m/s², the acceleration due to gravity
• <em>a</em> = 2.0 m/s², the acceleration of the elevator-object system
Solve for <em>m</em> :
25 N - <em>m</em> (9.8 m/s²) = - <em>m</em> (2.0 m/s²)
==> <em>m</em> = (25 N) / (9.8 m/s² - 2.0 m/s²) ≈ 3.2 kg
