The velocity of the mass at time, t = 1 s, is determined as 20 m/s.
<h3>
Magnitude of the force experienced by the body</h3>
The magnitude of the force experienced by the body is calculated as follows;
|F| = √(8² + 6²)
|F| = 10 N
<h3>Acceleration of the mass</h3>
From Newton's second law of motion;
F = ma
where;
- m is mass
- a is acceleration
a = F/m
a = 10 /0.5
a = 20 m/s²
<h3>Velocity of the mass after 1 second</h3>
v = at
v = 20 x 1
v = 20 m/s
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Answer:
0.758 N
Explanation:
mass of ball, = 36 g = 0.036 kg
radius, r = 19 cm = 0.19 m
tangential velocity, v = 200 cm / s = 2 m /s
The tension is the string is equal to the centripetal force acting on the ball.
The centripetal force acting on the ball is given by
T = 0.758 N
Thus, the tension in the string is given by 0.758 N.
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Since the initial velocity is 30 and the final is 0. 15 is the vave so you can use that with 1/2mv^2 to find the force
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