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nata0808 [166]
3 years ago
5

A pet store has cats. Here are their weights (in pounds).

Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

10.57142857 |Rounded is 10.6|

Step-by-step explanation:

The median is adding up all the numbers and diving it by how many sets their are.

10+13+8+9+13+14+7 = 74

74 ÷ 7 = 10.57 (rounded is 10.6)

Norma-Jean [14]3 years ago
6 0

Answer: 10.6

Step-by-step explanation: Add them up and divide by the number of terms. The total sum is 74. 74 divided by the total number of terms (7) is 10.57 rounded up to 10.6.

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Prove that there are infinitely many primes of the form 4k + 3, where k is a non-negative integer. [Hint: Suppose that there are
Simora [160]

Answer:

The prove is as given below

Step-by-step explanation:

Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.

Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).

ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.

Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).

Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.

So this indicates that there are infinite prime numbers of the form 4k+3.

6 0
3 years ago
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inysia [295]
You can only multiply and add with associative property. are you talking about distributive property or identity property
7 0
3 years ago
What is he diameter of a circle with a circumference of 235.5 cm
GalinKa [24]
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6 0
3 years ago
The sum of four times a number and 18 is the same as the difference of fourteen and twice a number
Citrus2011 [14]
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4 0
3 years ago
Ahmed is solving the following equation for xxx.
Dennis_Churaev [7]

Answer:

No

Step-by-step explanation:

An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.

Ahmed is solving 2\sqrt[3]{x-7}+11=3 for x.

His steps were:

\begin{aligned}2\sqrt[3]{x-7}&=-8\\  \sqrt[3]{x-7}&=-4\\  \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\  x-7&=-64 \end{aligned}

Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.

7 0
3 years ago
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