A generic element, Z, has two isotopes, 45Z and 47Z, and an average atomic mass of 45.36 amu. The natural abundances of the two
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Answer:
Molarity of the solution? 0,262 M.
Concentration of the potassium cation? 0,786 M.
Concentration of the phosphate anion? 0,262 M.
Explanation:
Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:
K₃PO₄ → 3 K⁺ + PO₄³⁻ <em>(1)</em>
Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.
There are 250 mL of solution≡0,25 L
The moles of K₃PO₄ are:
13,9 g of K₃PO₄ × = 0,0655 moles of K₃PO₄
The molarity of the solution is:
= 0,262 M
In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:
0,0655 moles×3 = 0,1965 moles
The concentration is:
= 0,786 M
The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M
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Answer:
See detailed explanation.
Explanation:
Hello.
In this case, since the electron configuration of potassium whose atomic number is 19 turns out:
We can see that the last level is 4 which has one electron, meaning that potassium has one valence electron. Moreover, since bromine's atomic number is 35, its electron configuration is:
We can see that the last level is also 4 and it has 2+5 = 7 valence electrons. In such a way, we infer that the valence electrons are computed by the electrons at the outer or last energy level of an element.
Regards.