Answer:
2.3 g NaCl
Explanation:
Given the concentration of the NaCl solution = 0.92% (w/v)
It means that 0.92 g of NaCl is present in 100 mL of water.
Thus,
100 mL of water contains 0.92 g of NaCl
To find, amount of NaCl in 250 mL of water
So,
1 mL of water contains of NaCl
250 mL of water contains of NaCl
<u>2.3 g of NaCl is present in 250 mL of this solution.</u>
Answer:
21.344%
Explanation:
For the given chemical reaction, 8 moles of the reactant should produce 4 moles of . However, 195 g of was produced instead. The molar mass of is 61.9789 g/mol.
Thus, the moles of produced = 195/61.9789 = 3.1462 moles
The percent error = [(Actual -Experiment)/Actual]*100%
The percent error = [(4.00 - 3.1462)/4.00]*100% = (0.85376/4.00)*100% = 21.344%
Conservation of energy
all of it should be transformed since the energy is convserved (neither destroyed nor created)
so answer is B