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lara31 [8.8K]
3 years ago
10

Write the net ionic equation for this reaction occurring in water: ammonium fluoride and magnesium chloride are mixed to form ma

gnesium fluoride and ammonium chloride. 1. no reaction occurs. 2. 2 nh+ 4 + 2 cl− → 2 nh4cl 3. 2 f− + mg2+ → mgf2 4. 2 nh4f + 2 cl− → 2 f− + 2 nh4cl 5. 2 f− + mgcl2 → mgf2 + 2 cl−
Chemistry
1 answer:
MAXImum [283]3 years ago
6 0

Correct answer: 3. Mg^{2+}(aq) + 2 F^{-}(aq) --> MgF_{2}(s)

The given chemical reaction is between ammonium fluoride and magnesium chloride to form magnesium fluoride and ammonium chloride.

The balanced chemical equation representing the reaction will be,

2NH_{4}F (aq) + MgCl_{2}(aq) -->MgF_{2} (s) + 2NH_{4}Cl (aq)

The complete ionic equation for the reaction: All the compounds soluble in water (aqueous) will split into ions, MgF_{2} will not split into ions as it is insoluble in water.

2 NH_{4}^{+}(aq) + 2 F^{-}(aq) + Mg^{2+}(aq) + 2 Cl^{-}(aq) --> MgF_{2}(s) + 2 NH_{4}^{+}(aq) + 2 Cl^{-}(aq)

The net ionic equation will be:

Mg^{2+}(aq) + 2 F^{-}(aq) --> MgF_{2}(s)

Here the spectator ions are NH_{4}^{+} and Cl^{-}


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The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−
barxatty [35]

Answer:

The reaction will be  non spontaneous at these concentrations.

Explanation:

AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)

Expression for an equilibrium constant K_c:

K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]

Solubility product of the reaction:

K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}

Reaction between Gibb's free energy and equilibrium constant if given as:

\Delta G^o=-2.303\times R\times T\times \log K_c

\Delta G^o=-2.303\times R\times T\times \log K_{sp}

\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]

\Delta G^o=69,117.84 J/mol=69.117 kJ/mol

Gibb's free energy when concentration [Ag^+] = 1.0\times 10^{-2} M and [Br^-] = 1.0\times 10^{-3} M

Reaction quotient of an equilibrium = Q

Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}

\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)

\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])

\Delta G=40.588 kJ/mol

  • For reaction to spontaneous reaction:  \Delta G.
  • For reaction to non spontaneous reaction:  \Delta G>0.

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

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Answer:

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Answer:

B: increase.

Explanation:

When we are considering two gases A and B in a container at room temperature .

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Hey there!
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