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Cerrena [4.2K]
3 years ago
7

What is the slope of the line y = -1/4x?

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0

The slope is -1/4. Hope this helps! Please mark brainliest! Thank you v much! :)

Papessa [141]3 years ago
5 0
The slope is -1/4 :)
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Find the zeros of the function.
rodikova [14]

Answer:

5 and -5

Step-by-step explanation:

Replace y with 0 and solve for x

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3 years ago
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if α,β are the roots of the equation x^{2}-3x+2=0 form an equation whose roots are (α+β)² & (α-β)²
GuDViN [60]

<u>Solution</u><u>:</u><u>-</u>

Let's find roots of x² - 3x + 2

=> x² - 3x + 2 = 0.

=> x² - x - 2x + 2 = 0.

=> x ( x - 1 ) -2 ( x - 1) = 0.

=> ( x - 1 ) ( x - 2 ) = 0.

=> x = 2, 1.

Now

  • ( a + ß )² = (2+1)²=3²=9
  • ( a - ß )² = ( 2 - 1 )² = 1² = 1.

So , equⁿ would be ,

=> x² - ( 9 + 1)x + 9×1=0.

<u>=> x² - 10x + 9=0.</u>

6 0
3 years ago
Which symbol correctly completes the statement? -7+2__3+(-)<br><br><br><br><br> &gt;,&lt;, =
OlgaM077 [116]

Answer:

Step-by-step explanation:

<

Hope that helps!

4 0
3 years ago
The graph of y= f(X) is shown below, what point could be used to find f(3)?
balandron [24]

Answer:

Point A

Step-by-step explanation:

The long that would be used to find f(3) is the point that shows the value of y when x = 3.

Looking at the graph given, the only point that shows the value of y when x = 3 is point A.

When x = 3, y = 0.

Therefore, f(3) = 0.

8 0
3 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
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