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Ilia_Sergeevich [38]
3 years ago
11

Determine the value for AB

Mathematics
2 answers:
mixer [17]3 years ago
6 0
<h3>Answer:  AB = 14</h3>

======================================================

Explanation:

Use the intersecting chord theorem

AO*OB = DO*OC

2x*10 = (x+3)*8

20x = 8x+24

20x-8x = 24

12x = 24

x = 24/12

x = 2

With that x value in mind, we can find the unknown lengths of each piece of each chord.

  • AO = 2x = 2*2 = 4
  • DO = x+3 = 2+3 = 5

Then notice how AO*OB = 4*10 = 40 while DO*OC = 5*8 = 40 as well. Both result in the same value (40) which helps verify the correct x value.

To wrap up the problem, we are looking for the length of chord AB, so,

AB = AO+OB = 4+10 = 14

grin007 [14]3 years ago
5 0

Answer:

x = 2

AB = 14

Step-by-step explanation:

2x(10) = 8(x+3)

20x = 8x + 24

subtract 8x from both sides

12x = 24

x = 2

Check:

4(10) = 8(5)

40 = 40

Correct

2x = 2 x 2 = 4

4 + 10 = 14

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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7 0
3 years ago
EASY MATH QUESTION <br><br> PLEASE HELP
Juli2301 [7.4K]
F(x)=3x^2-5 when x=-11
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3 0
3 years ago
Please help me with these!
Dvinal [7]

Answer:

Step-by-step explanation:

A1. C = 104°, b = 16, c = 25

Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°

A = 180-C-B = 37.6°

Law of Sines: a = c·sinA/sinC ≅ 15.7

A2. B = 56°, b = 17, c = 14

Law of Sines: C = arcsin[c·sinB/b] ≅43.1°

A = 180-B-C = 80.9°

Law of Sines: a = b·sinA/sinB ≅ 20.2

B1.  B = 116°, a = 11, c = 15

Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2

A = arccos{(b²+c²-a²)/(2bc) ≅26.5°

C = 180-A-B = 37.5°

B2. a=18, b=29, c=30

Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°

Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°

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6 0
2 years ago
Whats the answer &amp; how do I solve it ?
Veseljchak [2.6K]

Answer:

Area of rectangle = 225/2 or 112.5

Step-by-step explanation:

Given,

Consider a rectangle ABCD.

Let AC be a diagonal of rectangle of length   = 15

In triangle  ABC.

Sin 45° =height/hypotenuse   {SinФ = height / hypotenuse}

Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)

And height is AB

Therefore, sin 45° = AB/AC

or sin 45° = AB / 15

or 1/√2 = AB /15

AB = 15/√2

Similarly we can find Base (i.e BC) using cosine.

Cos 45° = Base/Hypotenuse

Cos 45° = BC / AC

or  1/√2 = BC/15

BC = 15/√2

Hence we got length of rectangle , AB= 15/√2

And width of rectangle , BC = 15/√2

Therefore, area of rectangle = Length × Width

Area of rectangle = 15/√2  ×   15/√2  = 225/2

Hence, area of rectangle = 225/2 = 112.5

6 0
3 years ago
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