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3 years ago

X/3 = 10 question 24 options: 10 3 30 7

Mathematics

2 answers:

Andrews [41]3 years ago

6 0

X ÷ 3 = 10

what you want to do is isolate for x by multiplying both sides by 3

10 × 3 = 30

So x = 30

Sveta_85 [38]3 years ago

3 0

$x/3=10$

$x=10*3$

$x=30$

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Find the area of a rhombus with a perimeter equal to 40 and a diagonal equal to 14 cm.

krek1111 [17]

Answer:

about 100 cm²

Step-by-step explanation:

The side length of the rhombus is 1/4 of the perimeter so is 10 cm. The length of half of the other diagonal will be the length of the leg of a right triangle with hypotenuse 10 and leg 7 (half the given diagonal).

d= √(10² -7²) = √51

Then the area of the rhombus is the product of this and the given diagonal:

A = (14 cm)(√51 cm) ≈ 99.98 cm²

The area of the rhombus is about 100 cm².

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If you were having a party and you expect each guest to eat 0.25 pounds of meat, how many pounds of meat should you buy if you e

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Answer:

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3 years ago

Bananas are $.59 a pound how much will 25 pounds of bananas cost

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- Question -

Bananas are $0.59 a pound. How much will 25 pounds of bananas cost?

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3 years ago

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4 years ago

Identify all of the root(s) of g(x) = (x2 + 3x - 4)(x2 - 4x + 29).

Gennadij [26K]

we have

$g(x)=(x^{2}+3x-4)( x^{2}-4x+29)$

To find the roots of g(x)

Find the roots of the first term and then find the roots of the second term

Step 1

Find the roots of the first term

$(x^{2}+3x-4)=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}+3x)=4$

Complete the square. Remember to balance the equation by adding the same constants to each side

$(x^{2}+3x+1.5^{2})=4+1.5^{2}$

$(x^{2}+3x+1.5^{2})=6.25$

Rewrite as perfect squares

$(x+1.5)^{2}=6.25$

Square root both sides

$(x+1.5)=(+/-)2.5$

$x=-1.5(+/-)2.5$

$x=-1.5+2.5=1$

$x=-1.5-2.5=-4$

so the factored form of the first term is

$(x^{2}+3x-4)=(x-1)(x+4)$

Step 2

Find the roots of the second term

$(x^{2}-4x+29)=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}-4x)=-29$

Complete the square. Remember to balance the equation by adding the same constants to each side

$(x^{2}-4x+4)=-29+4$

$(x^{2}-4x+4)=-25$

Rewrite as perfect squares

$(x-2)^{2}=-25$

Remember that

$i=\sqrt{-1}$

Square root both sides

$(x-2)=(+/-)5i$

$x=2(+/-)5i$

$x=2+5i$

$x=2-5i$

so the factored form of the second term is

$(x^{2}-4x+29)=(x-(2+5i))(x-(2-5i))$

Step 3

Substitute the factored form of the first and second term in g(x)

$g(x)=(x-1)(x+4)(x-(2+5i))(x-(2-5i))$

therefore

the answer is

the roots are

$x1=1\\x2=-4\\x3=(2+5i)\\x4=(2-5i)$

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4 years ago

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