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solniwko [45]
3 years ago
7

X/3 = 10 question 24 options: 10 3 30 7

Mathematics
2 answers:
Andrews [41]3 years ago
6 0
X ÷ 3 = 10

what you want to do is isolate for x by multiplying both sides by 3

10 × 3 = 30

So x = 30
Sveta_85 [38]3 years ago
3 0
x/3=10 

x=10*3 

x=30
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Find the area of a rhombus with a perimeter equal to 40 and a diagonal equal to 14 cm.
krek1111 [17]

Answer:

  about 100 cm²

Step-by-step explanation:

The side length of the rhombus is 1/4 of the perimeter so is 10 cm. The length of half of the other diagonal will be the length of the leg of a right triangle with hypotenuse 10 and leg 7 (half the given diagonal).

  d= √(10² -7²) = √51

Then the area of the rhombus is the product of this and the given diagonal:

  A = (14 cm)(√51 cm) ≈ 99.98 cm²

The area of the rhombus is about 100 cm².

6 0
4 years ago
If you were having a party and you expect each guest to eat 0.25 pounds of meat, how many pounds of meat should you buy if you e
kolbaska11 [484]

Answer:

7.5 pounds

Step-by-step explanation:

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3 years ago
Bananas are $.59 a pound how much will 25 pounds of bananas cost
Sergio039 [100]

- Question -

Bananas are $0.59 a pound. How much will 25 pounds of bananas cost?

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$2.95

- Explanation -

$0.59 * 5 = $2.95


6 0
3 years ago
Read 2 more answers
Plz help me i need help its for a test i give brailies (:
Anarel [89]
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8 0
4 years ago
Identify all of the root(s) of g(x) = (x2 + 3x - 4)(x2 - 4x + 29).
Gennadij [26K]

we have

g(x)=(x^{2}+3x-4)( x^{2}-4x+29)

To find the roots of g(x)

Find the roots of the first term and then find the roots of the second term

Step 1

Find the roots of the first term

(x^{2}+3x-4)=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+3x)=4

Complete the square. Remember to balance the equation by adding the same constants to each side

(x^{2}+3x+1.5^{2})=4+1.5^{2}

(x^{2}+3x+1.5^{2})=6.25

Rewrite as perfect squares

(x+1.5)^{2}=6.25

Square root both sides

(x+1.5)=(+/-)2.5

x=-1.5(+/-)2.5

x=-1.5+2.5=1

x=-1.5-2.5=-4

so the factored form of the first term is

(x^{2}+3x-4)=(x-1)(x+4)

Step 2

Find the roots of the second term

(x^{2}-4x+29)=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}-4x)=-29

Complete the square. Remember to balance the equation by adding the same constants to each side

(x^{2}-4x+4)=-29+4

(x^{2}-4x+4)=-25

Rewrite as perfect squares

(x-2)^{2}=-25

Remember that

i=\sqrt{-1}

Square root both sides

(x-2)=(+/-)5i

x=2(+/-)5i

x=2+5i

x=2-5i

so the factored form of the second term is

(x^{2}-4x+29)=(x-(2+5i))(x-(2-5i))

Step 3

Substitute the factored form of the first and second term in g(x)

g(x)=(x-1)(x+4)(x-(2+5i))(x-(2-5i))

therefore

the answer is

the roots are

x1=1\\x2=-4\\x3=(2+5i)\\x4=(2-5i)

8 0
4 years ago
Read 2 more answers
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