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3 years ago

What point can be used to create a right triangle

Mathematics

2 answers:

avanturin [10]3 years ago

8 0

Answer:

(-3,3)

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago

5 0

Answer:

$(-3,3)$

Step-by-step explanation:

Since this is a right triangle, it has to create a 90° angle. That means that we can find the points of intersection if we drew horizontal and vertical lines from points A and B.

One of the points of intersection is $(-8,-4)$ which is not an answer choice, but the other point of intersection, $(-3,3)$ is an answer choice.

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A group of friends wants to go to the amusement park. They have $116 to spend on parking and admission. Parking is $10.25, and t

Alexus [3.1K]

Answer:

2 people

Step-by-step explanation:

no. of people = x

total parking costs = 10.25x

total tickets cost = 35.25x

total = 10.25x + 35.25x

suppose 3 people go, then the total cost will be

10.25(3) + 35.25(3) = 136.5 and this is greater than 116

Suppose 2 people go then the cost will be

10.25(2) + 35.25(2) = 91 which is less than 116

so only 2 people can go.

7 0

2 years ago

Solve for (x) x+15=3x+5

dolphi86 [110]

Answer:

$x + 15 = 3x + 5 \\ 15 - 5 = 3x - x \\ 10 = 2x \\ \frac{10}{2} = \frac{2x}{2} \\ x = 5$

hope this helps....

8 0

3 years ago

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

3 years ago

Read 2 more answers

What percent of 642 is 321? and can you please add steps on how you got that answer thanks!

patriot [66]

To determine what percentage of 642 the number 321 is, we can follow the equation below.

(Smaller Number / Bigger Number)*100

We can plug the numbers into the equation to get our answer.

(321/642)*100 = 0.5 *(100) = 50%

So 321 is 50% of 642

7 0

3 years ago

Twice the product of -5 and a number

ryzh [129]

Answer:

Step-by-step explanation:

Twice the product of -5 and a number

2*(-5n)

8 0

2 years ago