Caleb draws 14 dogs on each of 4 posters.
Then,
Number of dogs drawn by caleb in the first instance = (14 * 4) dogs
= 56 dogs
Celeb drew 18 cats on each of 6 other posters.
Then
Number of cats drawn by Caleb in the first instance = (18 * 6) cats
= 108 cats
Again Caleb draws 5 more dogs on each poster with dogs.
Then,
The number of Dogs drwn in the second instance = (5 * 4) dogs
= 20 dogs
So, the total number of dogs drawn by Caleb = ( 56 + 20) dogs
= 76 dogs
Then the total number of cats and dogs drawn by Caleb = 108 + 76
= 184
Answer:
A. 0.6
B. 0.3
Step-by-step explanation:
For part A we use the the general probability addition rule for the union of two events that states
P(A∪B) = P(A) + P(B) − P(A∩B)
Making P(A∩B) the subject of the equation above
P(A∩B) = P(A) + P(B) − P(A∪B)
P(A∩B) = 0.8 + 0.7 - 0.9
P(A∩B) = 0.6
B.
The description in terms of A and B is:
P(A but not B) + P(B but not A) = P(A∩B') + P(B∩A')
where A' is compliment of set A and B' is compliment of set B
The above description means either it exceeds in July or in January (exactly in one of the two months)
P(A∩B') = 0.8 − 0.6
P(B∩A') = 0.7 − 0.6
P(A∩B') + P(B∩A') = 0.3
Answer:
The experimental probability of rolling a 2 is .
Step-by-step explanation:
Since you didn't give any statements, I'll make one myself.
P of rolling a 2 (experimental):
The experimental probability of rolling a 2 is .
Answer:
For 4 seconds the projectile will be in the air.
Step-by-step explanation:
The function f(x) = –10(x)(x – 4) represents the approximate height of a projectile launched from the ground into the air as a function of time in seconds, x.
Now, if the projectile stays for x seconds in the air then after x seconds its height will be zero.
Hence, 0 = - 10x(x - 4)
⇒ x = 0 or x = 4
Now, x cannot be 0 as at time = 0 the projectile starts its motion.
So, for 4 seconds the projectile will be in the air. (Answer)
Answer:
Step-by-step explanation:
A) = (35,?)
B) = POSITIVE
C) = 601