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3 years ago

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A negative charged particle of known magnitude q is placed in a uniform electric field of known strength E. What additional info

rmation is needed to determine the magnitude of the force on the particle?
a. The distance between the charged plates producing the uniform field.
b. The distance from the nearest plate to the charged particle.
c. The magnitude of the charges producing the field.
d. The mass of the negatively charged particle.
d. No additional information is needed.

1 answer:

olga_2 [115]3 years ago

8 0

Answer:d

Explanation:

Electric field is a region around charged particle where charged particle experience a force .

Magnitude of Force experienced by charged particle is given by

$F=q\cdot E$

where F=force experienced by charged particle

q=charge of particle

E=strength of electric field

If q and E are given then no additional information is needed to determine the magnitude of force.

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An aluminum cylinder with a radius of 2.7 cm and a height of 67 cm is used as one leg of a workbench. The workbench pushes down

soldier1979 [14.2K]

Answer:

$1.9\times 10^{-4}$

$1.2\times 10^{-4}\ m$

Explanation:

r = Radius = 2.7 cm

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A = Area = $\pi r^2$

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E = Young's modulus = $7\times 10^{10}\ Pa$

$\epsilon$ = Strain

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$\Delta L$ = Change in length

Young's modulus is given by

$E=\frac{\sigma}{\epsilon}\\\Rightarrow \epsilon=\frac{\sigma}{E}\\\Rightarrow \epsilon=\frac{\frac{3.2\times 10^4}{\pi 0.027^2}}{7\times 10^{10}}\\\Rightarrow \epsilon=0.0001996=1.9\times 10^{-4}$

Strain is $1.9\times 10^{-4}$

Strain is given by

$\epsilon=\frac{\Delta L}{L_0}\\\Rightarrow \Delta L=\epsilon\times L_0\\\Rightarrow \Delta L=1.9\times 10^{-4}\times 0.67\\\Rightarrow \Delta L=0.0001273\\\Rightarrow \Delta L=1.2\times 10^{-4}\ m$

The cylinder height decreases by $1.2\times 10^{-4}\ m$

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