So 80% of 15 games won equal 12 games won and 3 lost. This is because 15/10 = 1.5 and 1.5 x 8 =12.
For 30, you do the exact same thing but with 90% instead. 30/10 = 3. 3 x 9 = 27.
So they need to have won 27 games to get a 90% winning percentage out of 30 games.
But since the question asks how many MORE games they need to play, it'll be 27-12 = 15.
So they need to win 15 more games to get a 90% winning percentage
This is true
Think of two houses. If we say "the houses are identical" then the corresponding pieces must be the same (eg: the doors must be the same type out of the same material). In this analogy, the houses are the triangles, which are the overall structures. The doors are the angles since they are pieces of the overall structures. This is what CPCTC is saying
CPCTC = Corresponding Parts of Congruent Triangles are Congruent
Once again, the final answer is true.
10.5+(10.5*.4)=10.5+(4.2)=14.7lbs after the first month
Answer:
true
Step-by-step explanation:
Answer:
Let X be the number of times the target is hit. The probability P(X≥1) then equals 1 minus the probability of missing the target three times:
P(X≥1) = 1− (1−P(A)) (1−P(B)) (1−P(C))
= 1−0.4*0.3*0.2
= 0.976
To find the probability P(X≥2) of hitting the target at least twice, you can consider two cases: either two people hit the target and one does not, or all people hit the target. We find:
P(X≥2)=(0.4*0.7*0.8)+(0.6*0.3*0.8)+(0.6*0.7*0.2)+(0.6*0.7*0.8) = 0.788
Step-by-step explanation: