The simple principle for solute dissolution in a particular solvent is "like dissolves like". In the case of water, a solute will dissolve if it is polar. This is because water is a polar solvent. A polar substance is one which has particles that have a net charge on them. This net charge produces forces of attraction. When a polar solute is added to water, the water molecules are attracted to the solute particles and they attach to them. After attaching to the water molecules, the solute particles are dispersed throughout the water. Therefore, the answer is molecules or ions of a solute spread throughout the water molecules<span>.</span>
Answer : The molecular formula of the compound will be, 
Explanation :
Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.
Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :

As we are given that the empirical formula of a compound is
and the molar mass of compound is, 90.09 gram/mol.
The empirical mass of
= 1(12) + 2(1) + 1(16) = 30 g/eq


Molecular formula = 
Thus, the molecular formula of the compound will be, 
Answer:
Si ha mirado una tabla periódica, es posible que haya notado que la masa atómica de un elemento rara vez es un número par. Dupdo
Un Dalton, también conocido como unidad de masa atómica, es aproximadamente la masa de un solo protón o neutrón. Dupdo
Es decir, el deuterio tiene el doble de masa atómica que el protio y el tritio tiene tres veces la masa atómica del protio. Dupdo
El número bariónico, que es equivalente al número de masa atómica, debe permanecer constante para que se produzca una reacción.
Explanation:
Answer:
pH before addition of KOH = 4.03
pH after addition of 25 ml KOH = 7.40
pH after addition of 30 ml KOH = 7.57
pH after addition of 40 ml KOH = 8.00
pH after addition of 50 ml KOH = 10.22
pH after addition 0f 60 ml KOH = 12.3
Explanation:
pH of each case in the titration given below
(6) After addition of 60 ml KOH
Since addition of 10 ml extra KOH is added after netralisation point.
Concentration of solution after addition 60 ml KOH is calculated by
M₁V₁ = M₂V₂
or, 0.23 x 10 = (50 + 60)ml x M₂
or M₂ = 0.03 Molar
so, concentration of KOH = 0.03 molar
[OH⁻] = 0.03 molar
pOH = 0.657
pH = 14 - 0.657 = 13.34