Answer: Use Mixture Melting Point
Explanation:
A procedure called mixture melting point would be used to determine whether or not the suspected compound is identical to the unknown.
The two suspected compounds would need to be used to create a new mixture and determine the mixtures melting point. Compare this melting points with that of the unknown compound in order to determine which one of these two suspected compounds is identical to the unknown compound.
H2 is known to exist. For dihydrogen, H2, we can identify the frontier molecular orbitals (FMOs). The highest occupied molecular orbital (or HOMO) is the σ (sigma) 1s MO. The lowest unoccupied MO (LUMO) is the σ* (sigma star) 1s MO which is antibonding.
The statement that is not true about the exothermic reaction is that the potential energy of the product is higher than the potential energy of the reactant. That is option D.
<h3>What is an exothermic reaction?</h3>
An exothermic reaction is the reaction that releases heat to the environment which causes increase in the immediate environment.
The characteristics of exothermic reaction include the following:
- Activation energy of the forward reaction is smaller than the activation energy of the reverse reaction.
- Heat is released to the environment during reaction.
Since there is release of heat, the product will have a lower energy than the reactant.
Therefore, the statement that is not true about the exothermic reaction is that the potential energy of the product is higher than the potential energy of the reactant.
Learn more about exothermic reaction here:
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Answer:
1.373 mol H₂O
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
24.75 g H₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
<u /> = 1.37347 mol H₂O
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
1.37347 mol H₂O ≈ 1.373 mol H₂O