4 years ago

Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

2 answers:

lisabon 2012 [21]4 years ago

6 0

PV = nRT
P = ???
V = 2 liters.
n = 1 mol
T = 1000 K
R = 0.08205

P = nRT/V
P = 1 * 0.08205 * 1000 / 2
P = 41.03 atmospheres. That's a pretty big pressure. <<<< answer.

Kipish [7]4 years ago

4 0

pV = nRT

p = nRT/V

p= 1 x 0.08205 x 1000/ 2

p = 41.025 Pa

Edit: The unit should be atm instead of Pa, as pointed out by a nice human being.

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