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Dennis_Churaev [7]
3 years ago
12

The characteristics of two different types of reactions are shown below: Reaction A: Electrons are gained by the atoms of an ele

ment. Reaction B: Protons are lost by the atom of an element. Which statement is true about the atoms of the elements that participate in the two reactions? (5 points) Their identity changes in both Reaction A and Reaction B. Their identity changes in Reaction A but not in Reaction B. Their identity changes in Reaction B but not in Reaction A. Their identity remains the same in both Reaction A and Reaction B.
Chemistry
2 answers:
BabaBlast [244]3 years ago
5 0

Answer:

b

Explanation:

because it seems right

Inessa05 [86]3 years ago
4 0

Answer:

Their identity changes in Reaction B but not in Reaction A.

Explanation:

Reaction A describes a chemical reaction. Chemical reactions change the structures of substances and cause a gain or loss of electrons. Gaining or losing electrons will not change the identity of an atom.

Reaction B describes a nuclear reaction, which either splits the nucleus apart or combines two smaller nuclear.  Nuclear reactions cause a gain or loss of protons and neutrons by the atom of an element, thereby changing its identity.

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What is the volume of 64 g of oxygen gas 02 at STP
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Answer:

The volume would be 44.8 L

Explanation:

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3 years ago
Bromination occurs on alkene functional groups, but NOT on alkenes found within aromatic functional group, such as the phenyl ri
liq [111]

Answer:

When cinnamic acid react with bromine ,addition reaction rapidly occur on alkene functional group to form dibromo product

Explanation:

Phenyl ring is an aromatic hydrocarbon ,when aromatic hydrocarbons react with Cl2,Br2 or KMnO4 no reaction occur ,where as unsaturated hydrocarbon  like alkene react .Aromatic hydrocarbon with these reagents undenr different conditions undergoes subtituition reaction.They react with bromine in presence of lewis acid catalyst ferric bromide.

8 0
4 years ago
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under
sukhopar [10]

Answer:

\rho _2=0.22g/L

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}

It means we can compute the final density as shown below:

\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}

Now, we plug in to obtain:

\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L

Regards!

8 0
3 years ago
Which of the following processes will determine the number of moles in a sample? Dividing the mass of the sample by Avogadro's n
Olenka [21]

The answer is: Dividing the number of molecules in the sample by Avogadro's number.

The Avogadro’s number is the number of atoms in 12 grams of the isotope carbon-12 (¹²C).

Na is Avogadro number or Avogadro constant (the number of particles, in this example carbon, that are contained in the amount of substance given by one mole).

The Avogadro number has value 6.022·10²³ 1/mol in the International System of Units; Na = 6.022·10²³ 1/mol.

For example:

N(Ba) = 2.62·10²³; number of atoms of barium.

n(Ba) = N(Ba) ÷ Na.

n(Ba) = 1.3·10²⁴ ÷ 6.022·10²³ 1/mol.

n(Ba) = 2.158 mol; amount of substance of barium.

6 0
3 years ago
How many moles of Na are needed to produce 4 moles of NaCl in the reaction below?
IgorC [24]

Answer:

4 moles of Na are needed.

8 0
3 years ago
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