There are two forces acting on a parachute with a parachutist: the force of gravity and the air resistance. The force pulling the skydiver to the ground would be Wright force
In both cases less energy is required
But comparetively Mg require more energy than K
Let's see the electron configuration of Both
- [Mg]=1s²2s²2p⁶3s²=[Ne]3s²
- [K]=1s²2s²2p⁶3s²3p⁶4s¹=[Ar]4s¹
K has only one valence electron so very less ionization enthalpy so less energy required
Mg has 2 so more IE hence more energy required
Answer is A) Fulcrum
The fixed point that a lever rotates around is called the fulcrum.
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Answer:</h2>
0.126m
<h2>
Explanation:</h2>
According to Hooke's law, the force (F) acting on a spring to cause an extension or compression (e) is given by;
F = k x e -------------------(i)
Where;
k = the spring's constant.
From the question, the force acting on the spring is the weight(W) of the mass. i.e
F = W -----------------------(ii)
<em>But;</em>
W = m x g;
where;
m = mass of the object
g = acceleration due to gravity [usually taken as 10m/s²]
<em>From equation (ii), it implies that;</em>
F = W = m x g
<em>Now substitute F = m x g into equation(i) as follows;</em>
F = k x e
m x g = k x e ------------------(iii)
<em>From the question;</em>
m = m1 = 3.5kg
k = 278N/m
<em>Substitute these values into equation (iii) as follows;</em>
3.5 x 10 = 278 x e
35 = 278e
<em>Now solve for e;</em>
e = 35/278
e = 0.126m
Therefore, the distance the spring is stretched from its unstretched length (which is the same as the extension of the spring) is 0.126m
Answer:
What is the correct path of sperm cells through the male reproductive system?
Epididymis, seminiferous tubules, urethra, vas deferens
<u>Seminiferous tubules, epididymis, vas deferens, urethra
</u>
Urethra, seminiferous tubules, epididymis, vas deferens
Seminiferous tubules, vas deferens, epididymis, urethra
Hope this helps :)
Have a great day !
5INGH
Explanation:
