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2 years ago

15

A leaf falls from a tree. As you are watching the leaf fall, how can you tell that it has reached its terminal velocity?

1 answer:

Ratling [72]2 years ago

5 0

You can tell that it has reached its terminal velocity when D) the leaf is falling with a constant velocity as you are watching the leaf fall. The terminal velocity is a point of condition when an object's speed equalize the force of gravity. The terminal velocity condition could occur if there is no acceleration to the object's speed<span>.</span>

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Which of the following statements is true? The melting and freezing points of a substance are the same. The melting and boiling

insens350 [35]

<span>The melting and freezing points of a substance are the same.

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2 years ago

Read 2 more answers

A kickoff sends a football with an initial velocity of 25 m/s at an angle of 50

eduard

Answer:

The x-component of the velocity is 16.07 m/s

The y-component of the velocity is 19.15 m/s

Explanation:

Given;

initial velocity of the football, u = 25 m/s

angle of projection, θ = 50⁰

The x-component of the velocity (horizontal component) is given as;

$V_x = Vcos(50^0)\\\\V_x = 25 \ m/s \ \ \times \ \ 0.6428\\\\V_x = 16.07 \ m/s$

The y-component of the velocity (vertical component) is given as;

$V_y = Vsin(50^0)\\\\V_y = 25 \ m/s \ \ \times \ \ 0.766\\\\V_y = 19.15 \ m/s$

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2 years ago

A car in front of the school goes from rest to 27 m/s in 3.0 seconds. What is its acceleration (assuming

WITCHER [35]

The answer is 13.5 because 27÷3.0=13.5

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3 years ago

The moon has a mass of 7.34 . 102 kg and a radius of 1.74 . 106 meters. If you have a mass of 66 kg,

Ierofanga [76]

Answer:

$F=1.06\times 10^{-18}\ N$

Explanation:

Given that,

Mass of the Moon, $M=7.34\times 10^2\ kg$

Mass of the person, m = 66 kg

The radius of Moon, $r=1.74\times 10^6\ m$

We need to find the force between the person and the Moon. The formula for the gravitational force is given by :

$F=G\dfrac{Mm}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{7.34\times 10^2\times 66}{(1.74\times 10^6)^2}\\\\=1.06\times 10^{-18}\ N$

So, the required force is $1.06\times 10^{-18}\ N$ .

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3 years ago

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AVprozaik [17]

<span>The magnitude of her acceleration as she travels this 12 meters is 1.875m/s^2</span>

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3 years ago