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Ronch [10]
3 years ago
10

The displacement (in meters) of an object moving in a straight line is given by s=1+2t+1/4t^2^2, where t is measured in seconds.

Find the avg velocity over each time period, a) [1,3]
Physics
1 answer:
erica [24]3 years ago
4 0
 <span>(A) 
  s{ t } = (¼)t² + 2t + 1  ...  differentiate to get velocity versus time 

  v{ t } = (½)t + 2  ...  linearly increases with time 

(1) 

 Vavɢ{  a→b  } = [ v{ b } + v{ a } ] ⁄ 2 
 Vavɢ{ 1→3  } = [ v{ 3 } + v{1 } ] ⁄ 2 
 Vavɢ{ 1→3  } = [ (½)(3) + 2 + (½)(1) + 2 ]  ⁄  2 
 Vavɢ{ 1→3  } = 3 m/sec 

(II) and (III) are done the same way. 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~... 

(B) 
    v{ t } = (½)t + 2 

   v{1 } = (½)(1) + 2 
   v{1 } = 2.5 m/sec</span>
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Physics !!!!!!!!!!!!!!!!!
madreJ [45]

Answer:

1) v = -0.89 m/s

2) v = 36.5 m/s

Explanation:

1) Given

The mass of the boy, M = 45 Kg

The mass of the skateboard, m = 2 Kg

The initial velocity of the boy and skateboard is zero

According to the law of conservation of linear momentum

                              MV + mv = 0

                                           V = - mv/M

Substituting the given values in the above equation

                                          V = -2 x 20/ 45

                                             = -0.89 m/s

Hence, the velocity of the boy, v = -0.89 m/s

2) Given

The mass of the boy, M = 47 Kg

The mass of the skateboard, m = 8 Kg

The initial combined velocity of the boy and skateboard, u = 4.2 m/s

The boy jumped off from the skateboard with velocity, V = -1.3 m/s

According to the law of conservation of momentum,

                      MV + mv = (M + m)u

                                    v = [(M + m)u - MV] / m

Substituting the given values,

                                     v = [(47 + 8)4.2 - 47(-1.3)] / 8

                                        = 36.5 m/s

Hence, the velocity of the skateboard, v = 36.5 m/s

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4 years ago
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Answer:

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