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Ronch [10]
3 years ago
10

The displacement (in meters) of an object moving in a straight line is given by s=1+2t+1/4t^2^2, where t is measured in seconds.

Find the avg velocity over each time period, a) [1,3]
Physics
1 answer:
erica [24]3 years ago
4 0
 <span>(A) 
  s{ t } = (¼)t² + 2t + 1  ...  differentiate to get velocity versus time 

  v{ t } = (½)t + 2  ...  linearly increases with time 

(1) 

 Vavɢ{  a→b  } = [ v{ b } + v{ a } ] ⁄ 2 
 Vavɢ{ 1→3  } = [ v{ 3 } + v{1 } ] ⁄ 2 
 Vavɢ{ 1→3  } = [ (½)(3) + 2 + (½)(1) + 2 ]  ⁄  2 
 Vavɢ{ 1→3  } = 3 m/sec 

(II) and (III) are done the same way. 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~... 

(B) 
    v{ t } = (½)t + 2 

   v{1 } = (½)(1) + 2 
   v{1 } = 2.5 m/sec</span>
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A spotlight on the ground shines on a wall 12 meters away. If a man 2 meters high walks away from the spotlight towards the wall
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Answer: The length of the shadow on the wall is decreasing by 0.6m/s

Explanation:

the specified moment in the problem, the man is standing at point D with his head at point E.

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The two right triangles ΔABC and ΔADE are similar triangles. As such, their corresponding sides have equal ratios:

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Let's take derivatives of both sides:

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3 years ago
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