When a Frisbee is flying horizontally through the air, the speed of the air flowing over the Frisbee's top is
1 answer:
Group of answer choices.
A. higher than the speed of the air beneath it and the pressure on top of the Frisbee is greater than the pressure beneath it.
B. lower than the speed of the air beneath it and the pressure on top of the Frisbee is less than the pressure beneath it.
C. lower than the speed of the air beneath it and the pressure on top of the Frisbee is greater than the pressure beneath it.
D. higher than the speed of the air beneath it and the pressure on top of the Frisbee is less than the pressure beneath it.
Answer:
D. higher than the speed of the air beneath it and the pressure on top of the Frisbee is less than the pressure beneath it.
Explanation:
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
When a frisbee flies horizontally through the air, it experiences air above and beneath it. Also, there is a pressure acting on both on top and below the frisbee.
Typically, the air flowing over the top of the frisbee has a speed that is higher than the speed of the air beneath it.
Furthermore, the frisbee is able to remain in flight because the pressure on top of the frisbee is less than the pressure beneath it.
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Answer:
The work done is "2000 J".
Explanation:
The given values are:
Force,
F = 200 N
Mass,
m = 55 kg
Displacement,
d = 10 m
Now,
The work done will be:
⇒
On substituting the given values, we get
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Answer:
You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.
Explanation:
Given Values:
L = 50 cm = 0.5 m
H = 170 j/s
To find the diameter of the rod, we have to find the area of the rod using the following formula.
Here Tc = 100.0° C
k = 50.2
H = k × A ×
Solving for A
A =
A =
A = = 6.77 ×
m²
Now Area of cylinder is :
A = d²
solving for d:
d =
d = 9.28 cm