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vlabodo [156]
2 years ago
7

When a Frisbee is flying horizontally through the air, the speed of the air flowing over the Frisbee's top is

Physics
1 answer:
babymother [125]2 years ago
4 0

Group of answer choices.

A. higher than the speed of the air beneath it and the pressure on top of the Frisbee is greater than the pressure beneath it.

B. lower than the speed of the air beneath it and the pressure on top of the Frisbee is less than the pressure beneath it.

C. lower than the speed of the air beneath it and the pressure on top of the Frisbee is greater than the pressure beneath it.

D. higher than the speed of the air beneath it and the pressure on top of the Frisbee is less than the pressure beneath it.

Answer:

D. higher than the speed of the air beneath it and the pressure on top of the Frisbee is less than the pressure beneath it.

Explanation:

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Acceleration = \frac {Net \; force}{mass}

When a frisbee flies horizontally through the air, it experiences air above and beneath it. Also, there is a pressure acting on both on top and below the frisbee.

Typically, the air flowing over the top of the frisbee has a speed that is higher than the speed of the air beneath it.

Furthermore, the frisbee is able to remain in flight because the pressure on top of the frisbee is less than the pressure beneath it.

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Is it Conduction. Here's my theory e<span>nergy is transferred between the earth's surface and the atmosphere by Conduction, Convection and Radiation.</span>
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3 years ago
Joey drives along the 110 South freeway and notices a mile marker that reads 260 miles. He drives until he reaches the 150 mile
Nostrana [21]

Answer:

85 miles .

Explanation:

Displacement along the 110 South freeway = 260 - 150  =  110 miles

Displacement along the 110 North freeway = 150 - 175   = - 25 miles

Net displacement = 110 - 25 = 85 miles

So Joey's displacement from the 260 mile marker is 85 miles .

8 0
3 years ago
A train slows down as it pulls into a station. if the train is moving from your left to your right, what are the directions of t
navik [9.2K]

The directions of the vectors for velocity and acceleration are in the opposite directions.

  • The velocity vector is always in the direction of motion of the object. So, the direction of velocity is in the right from our point of view.
  • When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, the direction of velocity is in the left from our point of view.

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, the directions of the vectors for velocity and acceleration are in the opposite directions.

To know more about velocity and acceleration vectors

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3 0
1 year ago
How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​
-BARSIC- [3]

Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

 Mathematically;

        Power  = \frac{work done}{time}  

   Time  = \frac{work done}{power}  

 Work done  = weight x height

 convert mass to kg;

     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

          1000mm = 1m

          6.34 x 10⁴mm gives 63.4m

  Work done  = 14.7 x 9.8 x 63.4 = 9133.4J

  Time taken = \frac{9133.4}{2190}   = 4.2s

6 0
2 years ago
On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

W_1 = 57.96 J

Now similarly work done by frictional force

W_2 = Fdcos\theta

W_2 = 4*5cos180

W_2= -20 J

Now total work done on sled

W_{net}= W_1 + W2

W_{net} = 57.96 - 20 = 37.96 J

7 0
3 years ago
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