Answer:
- <u>4s</u>
- <u>50m/s (straight)</u>
Explanation:
I will answer in English.
The translated question is:
- <em>3. In a race whose route is straight, a motorcycle circulates for 30 seconds until it reaches a speed of 162.00km / h. If the acceleration remains the same, how long will it take to travel the remaining 200 meters to pass the finish line and at what speed will it do so?</em>
<h2>Solution</h2>
<u>1. Time</u>
First, you must calculate the acceleration, a, starting from rest (V₀ = 0), with a time fo 30 seconds, and final veloficty, V₁, of 162.00km/h.
Convert 162.00km/h to m/s:
- 162.00km/h × 1,000m/km × 3600s/h = 45m/s
- a = (V₁ - V₀)/t = (45m/s - 0) / (30s) = 1.5m/s²
Now, you can calculate the time to travel 200 meters
The most direct equation is;
Where you know:
Use the quadratic formula with a = 0.75, b = 45, and c = -200
Discard the negative value. The positive value is t = 4.1565s
Round to one significant figure: 4s ← answer
<u>2. Velocity</u>
The speed or magnitude of velocity may be calculated using the equation:
With:
- V₂ = 45m/s + 1.5m/s² × 4.1565s = 51m/s ≈ 50m/s, along the same straight line ← answer
Answer:
well actually that depends
Explanation:
that depends on the force of the launch of throw but a common would be like in 2-3secobds
The car will take 300 m before it stops due to applying break.
<h3>What's the relation between initial velocity, final velocity, acceleration and distance?</h3>
- As per Newton's equation of motion, V² - U² = 2aS
- V= final velocity velocity of the object, U = initial velocity velocity of the object, a= acceleration, S = distance covered by the object
- Here, U = 60 ft/sec, V = 0 m/s, a= -6 ft/sec²
- So, 0² - 60² = 2×6× S
=> -3600 = -12S
=> S = 3600/12 = 300 m
Thus, we can conclude that the distance covered by the car is 300 m before it stopped.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 6 ft/sec². How long will it take before the car stops?
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
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C. Both A. and B.
Explanation:
Statement A. Reducing the volume is true because of Boyle's law, which states that for a gas at fixed temperature, the pressure p and the volume V are inversely proportional:
Therefore, when the volume V is reduced, the pressure p increases.
Statement B. Adding more gas is also true: in fact, if we add gas into the container, we will have more molecules of the gas hitting the wall of the container. But the pressure of a gas is exactly given by this: by the collision of the molecules against the wall of the container, so the more the molecules of gas, the greater the pressure.
I am pretty sure that the only statement which is true for particles of the medium of an earthquake P-wave is being shown in the option : b)vibrate parallel to the wave, forming compressions and rarefactions. As you know, <span> it can be formed in two ways : from alternating </span>compressions<span> and </span>rarefactions<span> or </span><span>primary wave. I bet you will agree with me.</span>