All categories

2 years ago

Which of the following will cause an increase in gas pressure in a closed container?

2 answers:

7 0

The pressure in the gas container is increased by reducing the volume of the gas and also by adding more gas to the container.

Further Explanation:

The pressure of the gas is given by the Boyle’s law. It states that at constant temperature, the pressure of the gas is inversely proportional to the volume of the gas. The expression for the Boyle’s law is written as.

$\begin{gathered}p\propto \frac{1}{v} \\\Rightarrow pv = {\text{constant}} \\\end{gathered}$

Therefore, if the volume of the gas container is reduced, it will lead to the increase in the pressure of the gas inside the container.

On the other hand, if the amount of gas inside the container is increased, the number of molecules hitting the per unit area of the wall will be increased and this will also lead to the increase in the pressure of the gas inside the container.

Thus, the pressure of the gas inside the container is increased by decreasing the volume of the gas and also by increasing the amount of gas inside the container.

Learn More:

The amount of kinetic energy an object has depends on its brainly.com/question/137098
A property is a characteristic of a substance that can be observed and does not change the identity of the substance brainly.com/question/859623
According to Charles’s law, for a fixed quantity of gas at constant pressure, which of the given quantities is constant brainly.com/question/7316997

Answer Details:

Grade: High School

Chapter: Gas Laws

Subject: Physics

Keywords: Charles’s law, Boyle’s law, increase in pressure, closed container, reducing the volume, adding more gas, number of molecules, volume of gas.

Ludmilka [50]2 years ago

3 0

C. Both A. and B.

Explanation:

Statement A. Reducing the volume is true because of Boyle's law, which states that for a gas at fixed temperature, the pressure p and the volume V are inversely proportional:

$pV=const.$

Therefore, when the volume V is reduced, the pressure p increases.

Statement B. Adding more gas is also true: in fact, if we add gas into the container, we will have more molecules of the gas hitting the wall of the container. But the pressure of a gas is exactly given by this: by the collision of the molecules against the wall of the container, so the more the molecules of gas, the greater the pressure.

You might be interested in

What is the difference between vector and scalar ?

ddd [48]

The easiest, non-technical way to think about it is like this:

-- A scalar is a quantity that has a size but no direction.
Those include temperature, speed, cost, volume, distance, etc.

One number is all there is to know about it, and there's no way you can
add more of the same stuff to it that would cancel both of them out.

-- A vector is a quantity that has a size and also has a direction.
Those include force, displacement, velocity, acceleration, etc.

It takes more than one number to completely describe one of these.
Also, if you combine two of the same vector quantity in different ways,
you can get different results, and they can even cancel each other out.

Here are some examples. Notice that in each of these examples,
every speed has a direction that goes along with it. This turns the
scalar speed into a vector velocity.

If you're walking inside a bus, and the bus is driving along the road,
then your velocity along the road is the sum of your walking velocity
inside the bus plus the velocity of the bus along the road.

-- If you're walking north up the middle of the bus at 2 miles per hour
and the bus is driving north along the road at 20 miles per hour, then
your velocity along the road is 22 miles per hour north.

-- If you're walking south towards the back of the bus at 2 miles per hour
and the bus is driving north along the road at 5 miles per hour, then your
velocity along the road is 3 miles per hour north.

-- If you're walking south towards the back of the bus at 2 miles per hour
and the bus is just barely rolling north along the road at 2 miles per hour,
then your velocity along the road is zero.

-- If you're in a big railroad flat-car that's rolling north along the track
at 2 miles per hour, and you walk across the flat-car towards the east
at 2 miles per hour, then your velocity along the ground is 2.818 miles
per hour toward the northeast.

7 0

2 years ago

WILL GIVE THAT CROWN THINGY!

frutty [35]

Conservation of energy explains that energy can only be transferred between different forms of energy

3 0

2 years ago

Read 2 more answers

Suppose (for this statement only), that q is moved from the origin but is still within both the surfaces. The flux through both

o-na [289]

Answer:

-True - True - true - false -false - false

Explanation:

True The flow depends only on the charge into the surface, not on the relative position
True The two vectors are radial, so their relative direction do not changes
True It just depends on the charge inside
False, it only depends on the charge, not on the form from the integration surface
False, because if it has a load inside it can be considered in the center, but if the load is outside the flow lines change direction with respect to the surface
False The flow depends only on the load inside, not on its position

7 0

2 years ago

Two dogs fight over a bone. The larger of the two pulls on the bone to the right with a force of 42 N. The smaller one pulls to

tamaranim1 [39]

Answer:

Explanation:

35 N Small Dog <=======BONE=========> Bigger Dog 42 N

Fnet = Large Dog - small dog The forces are subtracted because they are acting in opposite Directions.

Fnet = 42 - 35

Fnet = 7 N

m = 2.5 kg

F = 7 N

a = ?

F = m * a

7 = 2.5 a

a = 7 / 2.5

a = 2.8 m/s^2

4 0

1 year ago

Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 1.6×104 m/s when at a distance

xz_007 [3.2K]

Answer:

v₂ = 7.6 x 10⁴ m/s

Explanation:

given,

speed of comet(v₁) = 1.6 x 10⁴ m/s

distance (d₁)= 2.7 x 10¹¹ m

to find the speed when he is at distance of(d₂) 4.8 × 10¹⁰ m

v₂ = ?

speed of planet can be determine using conservation of energy

K.E₁ + P.E₁ = K.E₂ + P.E₂

$\dfrac{1}{2}mv_1^2-\dfrac{GMm}{r_1} = \dfrac{1}{2}mv_2^2-\dfrac{GMm}{r_2}$

$\dfrac{1}{2}v_1^2-\dfrac{GM}{r_1} = \dfrac{1}{2}v_2^2-\dfrac{GM}{r_2}$

$v_2^2= v_1^2 + \dfrac{2GM}{r_2}-\dfrac{2GM}{r_1}$

$v_2= \sqrt{v_1^2 +2GM(\dfrac{1}{r_2}-\dfrac{1}{r_1})}$

$v_2= \sqrt{(1.6\times 10^4)^2 +2\times 6.67 \times 10^{-11}\times 1.99 \times 10^{30}(\dfrac{1}{4.8\times 10^{10}}-\dfrac{1}{2.7\times 10^{11}})}$

v₂ = 7.6 x 10⁴ m/s

3 0

2 years ago