3 years ago

Y = x2 -2 What is the Domain:

Mathematics

1 answer:

Elza [17]3 years ago

6 0

Answer:

all real numbers

Step-by-step explanation:

The domain is the values that x can take

x can be any real number

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plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

4 years ago

Write an equation in slope intercept form of the line containing the points (3,-1) and<br>(6,7).

liq [111]

Answer:

m - 8/3

Step-by-step explanation:

Find the slope of the line between (-3,1) and (6,7) using m = (y2 - y1) / (x2-x1)

which is the change of "y" over the change of "x"

m = (7 - (-1) / 6 - (3)

m = 8/3

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3 years ago

Please Help!!!<br><br> What two numbers go there?

marshall27 [118]

The answer is 9/7!! Hope it helps

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3 years ago

lisa is 50. she is twice as old as her little brother sam. sam is 3 times younger than their oldest sibling Brad. How old are Br

Tamiku [17]

Lisa is 50 years

Sam is 50 / 2 = 25 years

Brad is 25 * 3 = 75 years

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3 years ago

Read 2 more answers

What does y equal in 8x+y=15

Vinil7 [7]

You need two equation to solve for two variables exactly.

Using this one equation alone y=15-8x.

Do you have another equation?

8 0

4 years ago