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nydimaria [60]
3 years ago
5

The art teacher asked her students to cut out 1045 apples and 1463 leaves from construction paper five apples can be cut from a

sheet of paper 7 Leaves can be cut from a sheet of paper how many sheets of paper does she need write equation to find the unknown then find the unknown
Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Answer: There are 418 sheets needed to cut all the required apples and leaves.

Explanation:

Since we have given that

Number of apples = 1045

Number of leaves = 1463

From a sheet of paper,

Number of apples can be cut = 5

Number of leaves can be cut = 7

Let the number of sheets of paper be x

So,

Number of sheets of paper required to cut 1045 apples is given by

\frac{1045}{5}=209

Similarly,

Number of sheets of paper required to cut 1463 leaves is given by

\frac{1463}{7}=209

So, total number of sheets is required to cut 1045 apples and 1463 leaves is given by

209+209=418

Hence, there are 418 sheets needed to cut all the required apples and leaves.

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Answer:

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Step-by-step explanation:

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There is 5/6 of an apple pie left from dinner. Tomorrow, victor plans to eat 1/6 of the pie that was left. How much of the whole
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5/6 - 1/6 = 4/6 reduced to 2/3
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2) The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart. A student as
Serggg [28]

Answer:

The calculated value z =  9.4451 > 1.96 at 5% level of significance.

Null hypothesis is rejected at 5% level of significance

yes there is  difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

Step-by-step explanation:

<u>Explanation</u>:-

<u>Step:- (1)</u>

The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart.

A student asked a random sample of teachers in 2018 and found 165 had smart-phones, 80 had a cell phone

The first sample proportion

                                  p_{1} = \frac{80}{165} = 0.4848

A student asked a random sample of teachers in 2018 and found 165 had smart-phones,5 had no cell phone

The second sample proportion

                                p_{2} = \frac{5}{165} = 0.03030

<u>Step :-(ii)</u>

<u>Null hypothesis :H₀</u>: Assume that there is no difference in the distribution of types of cell phones for the teachers in 2018

H₀ : p₁ = p₂

<u>Alternative hypothesis :H₁</u>

H₁ : p₁ ≠ p₂

<u>Level of significance : ∝=0.05</u>

The tabulated value z=1.96

<u>Step:-(iii)</u>

The test statistic

                       Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }  } +\frac{1}{n_{2} } )} }

   where p = \frac{n_{1}p_{1} +n_{2} p_{2}  }{n_{1} + n_{2} }

              q = 1-p

 In given data n₁ = n₂ = n

              p = \frac{165 (0.4848)+165 (0.03030  }{165 + 165}

   on calculation , we get      p =  0.2655

                                                 q =1-p = 1-0.2655

                                                  q = 0.7345

                 

                    Z = \frac{0.4848 -0.030}{\sqrt{0.2655X0.7345(\frac{1}{165 }  } +\frac{1}{165} )} }

                    Z =   9.4451

The calculated value z =  9.4451 > 1.96 at 5% level of significance.

<u>Conclusion:</u>-

Null hypothesis is rejected at 5% level of significance

yes there is  difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

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Answer:

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Answer:

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Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then

x = 180° - (32 + 24)° = 180° - 56° = 124°

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