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Alexxx [7]
3 years ago
8

A circular tabletop has a circumference of 94.2 inches. What is its area? Approximate Π as 3.14.

Mathematics
2 answers:
sattari [20]3 years ago
5 0
A≈706.14in² hope it helps
Minchanka [31]3 years ago
4 0

Answer:

706.5

Step-by-step explanation:

I had this question on my online school and I got it right

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AB is tangent to circle O at A. The diagram is not drawn to scale. if AO=21 and BC=14, what is AB?
barxatty [35]
Ab would equal to 7 using tringle steps
7 0
3 years ago
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Price-club sells a 12-ounce box of crackers for $2.59 and Shop Mart sells 1-pound box of crackers for $4.68. The unit price at P
Vesna [10]

Answer:

The unit price at Price-Club is $0.2158 per ounce.

The unit price at Shop Mart is $0.2925 per ounce.

Step-by-step explanation:

Price Club:

12-ounce box of crackers for $2.59

So

12 ounces - $2.59

1 ounce - x

12x = 2.59

x = \frac{2.59}{12}

x = 0.2158

The unit price at Price-Club is $0.2158 per ounce.

Shop Mart:

1-pound box of crackers for $4.68.

1 pound is 16 ounces. So

16 ounces - $4.68

1 ounce - x

16x = 4.68

x = \frac{4.68}{16}

x = 0.2925

The unit price at Shop Mart is $0.2925 per ounce.

8 0
3 years ago
Find 6m if m = 5/13<br><br> Please help<br><br> Leave your answer in fraction form please
gladu [14]

Step-by-step explanation:

or, 6m=5/13

or, m=5/13 ×6m

m=30/13

3 0
3 years ago
Find the area of a triangle with points (-8,8) , (10,-2), and (-8,-8)
tatuchka [14]

Answer:

144

Step-by-step explanation:

Base:16

Height: 18

Triangle area formula: (bxh)/2

16x18=288

288/2=144

8 0
2 years ago
fabiana decides to save the money she is earning from her after school job for college. she makes an initial contribution of 300
Oxana [17]

Answer:

A. Total Money Contributed after n months = \$ 3000 + \$ (500\times n)

B. Total Money Contributed after 24 months = \$ \ 15000

Step-by-step explanation:

Given:

Initial contribution = \$\ 3000

each month contribution =\$\ 500

After 1 month contributed = \$\ 3000 + \$\ 500 \times 1= \$ \ 3500

Solving for Part A

let n be the number of months

∴ Total Contribution after n months = Initial contribution + (each month contribution \times Number of months = \$\ 3000 + \$\ 500 \times n

Solving for Part A

Now n= 24 months

∴ Total Contribution after 24 months = \$\ 3000 + \$\ 500 \times 24 = \$\ 3000 + \$\ 12000= \$\ 15000

3 0
3 years ago
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